Answer: -1
Step-by-step explanation:
Answer:
0.000221
Step-by-step explanation:
Using the z score formula when a random number of samples is given =
z = (x-μ)/σ/√n, where
x is the raw score
μ is the population mean
σ is the population standard deviation = 7
n is random number of samples = 83
Note that:2.2 dollars = x-μ
z = 2.2/7/√8.3
z = 3.51402
Probability value from Z-Table:
P(x<27.7) = 0.99978
P(x>27.7) = 1 - P(x<27.7) = 0.00022069
Approximately = 0.000221
Hence, the probability that the sample mean would differ from the true mean by greater than 2.2 dollars if a sample of 83 5-gallon pails is randomly selected is 0.000221
The answer is the third option
x+y=120_______1
x=4*y_________2
x=4y
substitute 4y for x in equation 1
`4y+y=120
5y=120
eliminate the coefficient of y
y=120/5
y=24
now,input 24 for y in equation 2
`x=4y
x=4*24
x=96
thus, the numbers are
96 and 24
From V= 4/3*pi*r^3
<span>dV/dt = 4pi(r^2)dr/dt </span>
<span>so when dV/dt=30 and r = 19 </span>
<span>30 = 4pi(361)dr/dt </span>
<span>dr/dt = 30/[4pi(361)] </span>
<span>now in </span>
<span>A = 4pir^2 </span>
<span>dA/dt = 8pi(r)dr/dt </span>
<span>= 8pi(19)*30/[4pi(361)] </span>
<span>= you finish it.</span>
<span>HOPE THIS HELPS.
</span>
