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Ahat [919]
3 years ago
6

HELP AGAIN............

Mathematics
1 answer:
dybincka [34]3 years ago
3 0

Answer:

  $0.55

Step-by-step explanation:

Since you're only interested in the "a" variable, you can eliminate r from the system by subtracting 5 times the second equation from 12 times the first.

  12(5r +15a) -5(12r +11a) = 12(10.5) -5(11.45)

  60r +180a -60r -55a = 126 -57.25

  125a = 68.75

  68.75/125 = a = 0.55 . . . . . . . the cost of each apple

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A certificate of deposit earns 1% interest every three months. The interest is compounded.
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A certificate of deposit earns 1% interest every three months. The interest is compounded.


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A. 37,153.21
5 0
3 years ago
Read 2 more answers
6 (r - 4) + r + 30 - 7r
GrogVix [38]
6r-24+r+30-7r (the we divide the regular numbers on one side and the others on the other side)Like this:
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And the final answer is 6
8 0
3 years ago
15/40 in lowest term I need it so bad now
Vesnalui [34]

In order to reduce ANY fraction to lowest terms, find any common factors
of the numerator and denominator, and divide them both by it.  If they still
have a common factor, then divide them by it again.  Eventually, they won't
have any common factor except ' 1 ', and then you'll know that the fraction is
in lowest terms.

Do  15  and  40  have any common factors ?
Let's see . . .

The factors of  15  are  1,  3,  <em>5</em>, and  15 .
The factors of  40  are  1,  2,  4,<em>  5</em>,  8,  10,  20, and  40 .

Ah hah !  Do you see that ' <em>5</em> ' on both lists ?  That's a common factor.

So  15/40  is NOT in lowest terms.

Divide the numerator and denominator both by  5 :

       15 / 40  =<em>  3 / 8</em>

3  and  8  don't have any common factor except ' 1 '. 
So  3/8  is the same number as  15/40, but in lowest terms.


5 0
3 years ago
Read 2 more answers
If y-3x=9, 7x+y=25, what is the value of x and y?
lianna [129]

\bold{\rm{Given}}\text{ : If y - 3x = 9, 7x + y = 25, what is the value of x and y}?

\bold{\rm{Solution}} \text{: We'll solve this by substitution method}

\dashrightarrow  y - 3x = 9 \\  \\  \dashrightarrow   \boxed{y = 9 + 3x } \qquad .. \sf eq(1)

\text{we got the value of y now getting the value of x}

\looparrowright 7x + y = 25 \\  \\  \looparrowright 7x = 25 - y \\  \\  \looparrowright  \boxed{x =   \frac{25 - y}{7}} \qquad .. \sf eq(2)

\text{Now, putting y = 9 + 3x in eq(2)}

\hookrightarrow  x =  \frac{25 - y}{7}   \\  \\ \hookrightarrow  x =  \frac{25 - 9 + 3x}{7}  \\  \\ \hookrightarrow  7x =  25 - 9 + 3x \\  \\ \hookrightarrow  7x - 3x =  16 \\  \\ \hookrightarrow  4x = 16 \\  \\ \hookrightarrow  x =  \frac{16}{4}  \\  \\ \star \quad  \boxed{ \green{ \frak{ x = 4}}}

\text{Now we know the value of x, for getting y we need to put x in eq(1)}

: \implies y = 9 + 3x \\  \\   : \implies y = 9 + 3(4) \\  \\  : \implies y = 9 + 12  \\  \\    \star \quad  \boxed{\frak{  \green{y = 21}}}

\text{Hence, values of x and y are} \:  \frak{ \green{4}}  \: \text{and} \:  \frak{ \green{21}} \: \text{respectively}.

4 0
2 years ago
How does d transfer in y=(x-d)^2+7
kompoz [17]

Step-by-step explanation:

y=(x-d)²+7

y-7=(x-d)²

√(y-7)=x-d

d=x-√(y-7)

I would appreciate if my answer is chosen as a brainliest answer

8 0
2 years ago
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