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Roman55 [17]
3 years ago
9

Of all the people that attend movies 67% are in the 12-29 age group. At one theater, 300 people attended a showing of a certain

movie. How many were in the 12-29 age group?
Mathematics
1 answer:
suter [353]3 years ago
6 0
67 multiplied by 3 is 201, so there is 201 people in the age group 12-29. Also, 67% is approximately two thirds, and we can see that reflected in our answer.
You might be interested in
If sin theta =1/4, theta in quadrant II, find the exact value of cos[theta +pi/6]
Mashcka [7]
Using cos addition formula:
use x for theta
cos(x+π/6)=cosx*cos(π/6)-sinx*sin(π/6)
sinx=1/4
cosx=√15/4
cos(π/6)=√3/2
sin(π/6)=1/2
cos(x+π/6)=(√15/4*√3/2)-(1/4*1/2)
cos(x+π/6)=(√45/8)-(1/8 )
cos(x+π/6)=(√45-1)/8)
6 0
3 years ago
Find the average rate of change of an exponential function f (x) over the interval 1 ≤ x ≤ 3.
Neko [114]

Answer:

Option b. 12

Step-by-step explanation:

we know that

To find the average rate of change, we divide the change in the output value by the change in the input value

The average rate of change is equal to

\frac{f(b)-f(a)}{b-a}

In this problem we have

a=1

b=3

f(a)=f(1)=1  

f(b)=f(3)=25

Substitute

\frac{25-1}{3-1}=12

8 0
4 years ago
Find the area of this rectangle.<br> 5 in<br> 10 in<br> A = [?] in?
Talja [164]

Answer:

A=50

Step-by-step explanation:

5x10=50in

4 0
3 years ago
Read 2 more answers
2. Suppose that you are looking for a student at your college who lives within five miles of you. You know that 55% of the 25,00
svlad2 [7]

Using the binomial distribution, it is found that:

a) There is a 0.0501 = 5.01% probability that you need to contact four people.

b) You expect to contact 1.82 students until you find one who lives within five miles of you.

c) The standard deviation is of 1.22 students.

d) There is a 0.3369 = 33.69% probability that 3 of them live within five miles of you.

e) It is expected that 2.75 students live within five miles of you.

For each student, there are only two possible outcomes. Either they live within 5 miles of you, or they do not. The probability of a student living within 5 miles of you is independent of any other student, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 55% of the students live within five miles of you, thus p = 0.55.

Item a:

This probability is P(X = 0) when n = 3(none of the first three living within five miles of you) multiplied by 0.55(the fourth does live within five miles), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.55)^{0}.(0.45)^{3} = 0.091125

p = 0.091125(0.55) = 0.0501

0.0501 = 5.01% probability that you need to contact four people.

Item b:

The expected number of trials in the binomial distribution until q successes is given by:

E = \frac{q}{p}

In this problem, p = 0.55, and 1 trial, thus q = 1, hence:

E = \frac{1}{0.55} = 1.82

You expect to contact 1.82 students until you find one who lives within five miles of you.

Item c:

The standard deviation of the number of trials until q successes are found is given by:

S = \frac{\sqrt{q(1 - p)}}{p}

Hence, since q = 1, p = 0.55:

S = \frac{\sqrt{0.45}}{0.55} = 1.22

The standard deviation is of 1.22 students.

Item d:

This probability is P(X = 3) when n = 5, hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{5,3}.(0.55)^{3}.(0.45)^{2} = 0.3369

There is a 0.3369 = 33.69% probability that 3 of them live within five miles of you.

Item e:

The expected value of the binomial distribution is:

E(X) = np

Hence, since n = 5, p = 0.55:

E(X) = 5(0.55) = 2,75

It is expected that 2.75 students live within five miles of you.

A similar problem is given at brainly.com/question/25343741

7 0
3 years ago
a set of angles has a ratio of 5:2 if the larger angle measures 105 degrees then what is the measure of the smaller angle?
Sphinxa [80]
42 degrees. Divide 105 by 5 and get 21 and then multiply it by 2.
7 0
3 years ago
Read 2 more answers
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