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Lapatulllka [165]
3 years ago
7

)The scatter plot shows the number of fliers mailed out in a month (in thousands) and the number of new customers small business

es had in that same month:
What will most likely be the effect on the number of new customers that a small business has if the number of fliers the business sends increases?  The number of new customers will decrease because the graph shows a negative association. The number of new customers will increase because the graph shows a positive association. The number of new customers will increase because the graph shows a negative association. The number of new customers will decrease because the graph shows a positive association.

Mathematics
2 answers:
muminat3 years ago
7 0
Well...just look at ur graph...it appears that the more fliers u send out, the more customers there are....therefore,when the fliers are increased,  the number of new customers will increase because the graph shows a positive association
saveliy_v [14]3 years ago
5 0

Answer: The answer is "The number of new customers will increase because the graph shows a positive association."

Step-by-step explanation: I know because it makes total sense if new customers will increase, plus I just did this.

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Answer:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

Step-by-step explanation:

x^{2}+6x-5=0

we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power:  3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

x^{2}+6x+9-9-5=0

we have:

(x+3)^{2}-9-5=0

(x+3)^{2} = 14

lets apply square root on both sides of the equation:

\sqrt{(x+3)^{2}}=\sqrt{14}

we know:

\sqrt{a^{2}} = abs(a)

so we have:

abs(x+3)=\sqrt{14}

from where two solutions are obtained

x_{1} + 3 =\sqrt{14} \\\\x_{2} + 3 =-\sqrt{14}

finally we have:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

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3 years ago
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3 years ago
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Answer:

Nothing further can be done with this topic. Please check the expression entered or try another topic.

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