21g-6f-8g
13g-6f is the answer
combine like terms
Answer:
It's Ok
Step-by-step explanation:
Mark me brainliest :>
Answer:
y = 2cos5x-9/5sin5x
Step-by-step explanation:
Given the solution to the differential equation y'' + 25y = 0 to be
y = c1 cos(5x) + c2 sin(5x). In order to find the solution to the differential equation given the boundary conditions y(0) = 1, y'(π) = 9, we need to first get the constant c1 and c2 and substitute the values back into the original solution.
According to the boundary condition y(0) = 2, it means when x = 0, y = 2
On substituting;
2 = c1cos(5(0)) + c2sin(5(0))
2 = c1cos0+c2sin0
2 = c1 + 0
c1 = 2
Substituting the other boundary condition y'(π) = 9, to do that we need to first get the first differential of y(x) i.e y'(x). Given
y(x) = c1cos5x + c2sin5x
y'(x) = -5c1sin5x + 5c2cos5x
If y'(π) = 9, this means when x = π, y'(x) = 9
On substituting;
9 = -5c1sin5π + 5c2cos5π
9 = -5c1(0) + 5c2(-1)
9 = 0-5c2
-5c2 = 9
c2 = -9/5
Substituting c1 = 2 and c2 = -9/5 into the solution to the general differential equation
y = c1 cos(5x) + c2 sin(5x) will give
y = 2cos5x-9/5sin5x
The final expression gives the required solution to the differential equation.
Answer:
3000 meters
Step-by-step explanation:
1 kilometer = 1000 meters
1 kilometers = every 20 minutes
3× 1000 meters= 20 min ×3
3000 meters = 60 min/ 1 hour
Answer:
Step-by-step explanation:
This is simply a units conversion problem. It gives us for the number of passengers, the number of seats per carriage and the number of carriages per train. To change the units from passengers to trains without changing the value, we use the multiplicative identity (that is, 1).
350000 passengers
(350000 passengers) * 1
(350000 passengers) * ((1 carriage)/(32 passengers)) * ((1 train)/(15 carriages)
[note: passengers and carriages cancel. Leaving only trains]
(350000)*(1/32)*(1/15) trains [note: I write this way to paste into MS Excel]
729.1667 trains [oh, but don’t just round this number either up or down]
729 full trains can carry 729*32*15 = 349920 passengers
730 full trains can carry 730*32*15 = 350400 passengers
Now, we can say that 730 trains are adequate to carry 350000 passengers.
