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olya-2409 [2.1K]
3 years ago
10

What is the distance between points P begin ordered triple (-2,1,3) end ordered triple and Q begin ordered triple -(1,4,-2) end

ordered triple to the nearest tenth?
Answer is 5.9
I need to know why the answer is rational (meaning why is it correct)
Mathematics
1 answer:
Gnom [1K]3 years ago
4 0
Because its a function

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Find the volume of each of the following cubes. a. s = 7 kilometers b. s = 11 yards
nadya68 [22]

Answer:

Part 1) V=343\ km^{3}

Part 2) V=1,331\ yd^{3}

Step-by-step explanation:

we know that

The volume of a cube is equal to

V=s^{3}

where

s is the length of the cube

Part 1)

we have

s=7\ km

substitute in the formula

V=7^{3}

V=343\ km^{3}

Part 2)

we have

s=11\ yd

substitute in the formula

V=11^{3}

V=1,331\ yd^{3}


6 0
3 years ago
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The quotient of 10 and x​
Naddik [55]

Answer:

it would be either 10/x or x/10 depending on the order

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Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

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What shape has<br> 4 equal sides and<br> No right angles
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