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Vadim26 [7]
3 years ago
9

Given f (x) = 5x + 1, find f(0).

Mathematics
1 answer:
Andrej [43]3 years ago
7 0

Answer:

1

Step-by-step explanation:

5(0)+1=1 because 5x0=0 then add the 1

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A hiker averages 1.4 mph downhill on a mountain trail and 0.8 mph uphill. Find the total time spent hiking in terms of the dista
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Answer:

V=d/t.

V=(1.4)(0.8)÷8m/s

=0.14

Step-by-step explanation:

bali yung divide ay guhit sa baba

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3 years ago
Francis is at the state fair. A fair concession stand is selling funnel cakes for $3.50 and deep-fried Oreos for $2.00. Write an
VladimirAG [237]

The equation that models the number of funnel cakes and Oreos he can buy is 3.50x + 2.0y = 42

Data given;

  • Cost of cakes = $3.50
  • Cost of Oreos = $2.00
  • The total amount spent = $42.00
<h3>What is the Equation</h3>

To solve this problem, we just need to write out an equation to show how he can spend $42.00 in the fair on Oreos and Cakes.

Let x represent the cakes

Let y represent the Oreos

The equation is thus;

3.50x + 2.0y = 42.00

The equation that shows the number of Cakes and Oreos can by is

3.50x + 2.0y = 42

Learn more about equation here;

brainly.com/question/13729904

3 0
2 years ago
Please Help!!!!
jek_recluse [69]

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(6, -4)

Step-by-step explanation:

The ice cream shop should be between the school and hospital.

4 0
3 years ago
Read 2 more answers
Simplify the algebraic expression.<br> 5(5x-3) - 6x
lord [1]
19x-15 is the answer
8 0
3 years ago
Find four distinct complex numbers (which are neither purely imaginary nor purely real) such that each has an absolute value of
Luda [366]

Answer:

  • 0.5 + 2.985i
  • 1 + 2.828i
  • 1.5 + 2.598i
  • 2 + 2.236i

Explanation:

Complex numbers have the general form a + bi, where a is the real part and b is the imaginary part.

Since, the numbers are neither purely imaginary nor purely real a ≠ 0 and b ≠ 0.

The absolute value of a complex number is its distance to the origin (0,0), so you use Pythagorean theorem to calculate the absolute value. Calling it |C|, that is:

  • |C| = \sqrt{a^2+b^2}

Then, the work consists in finding pairs (a,b) for which:

  • \sqrt{a^2+b^2}=3

You can do it by setting any arbitrary value less than 3 to a or b and solving for the other:

\sqrt{a^2+b^2}=3\\ \\ a^2+b^2=3^2\\ \\ a^2=9-b^2\\ \\ a=\sqrt{9-b^2}

I will use b =0.5, b = 1, b = 1.5, b = 2

b=0.5;a=\sqrt{9-0.5^2}=2.958\\ \\b=1;a=\sqrt{9-1^2}=2.828\\ \\b=1.5;a=\sqrt{9-1.5^2}=2.598\\ \\b=2;a=\sqrt{9-2^2}=2.236

Then, four distinct complex numbers that have an absolute value of 3 are:

  • 0.5 + 2.985i
  • 1 + 2.828i
  • 1.5 + 2.598i
  • 2 + 2.236i
4 0
3 years ago
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