Answer:
4 cm.
Step-by-step explanation:
Given:
A box has a volume of 308 cm cubed.
Its height is 4 cm greater than its length.
Its length is 3 cm greater than its width.
Question asked:
What is the width of the box?
<u>Solution</u>:
Let width = 
Length = 
Height = 
<u>As we know:</u>
<u />

As width can never be in negative, 
By substituting the value:-
Width =
= 4 cm
Thus, width of the box is 4 cm.
This statement is false<span>. Because the </span>base angles<span> of an </span>isosceles triangle<span> are</span>congruent<span>, if one </span>base angle<span> is a right </span>angle<span> then both </span>base angles<span> must be right</span>angles<span>. It is impossible to have a </span>triangle<span> with two right (90^\circ)</span>angles<span>.</span>
The entire length of the line, AE, is 38. We are asked to find the length from point C to point E.
AB and BC are both 5 units in length. The length from point B to point D is 17. So, if we subtract 5 from 17, we get 12.
The length between point C and point D is 12. DE appears to be of the same distance. So, DE is also 12.
12 + 12 = 24
So, CE = 24.