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Paha777 [63]
2 years ago
15

Describe the dimension of two different prisms that each have a volume of 2,400cubic centimeters. Then draw each prism.

Mathematics
1 answer:
salantis [7]2 years ago
6 0
First do 2400 ÷ 3 = 800 then make a prism as the width as 800 and the length as 800 and height as 800
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Simplify and then classify by degree and number of terms<br> 2x+3x^2(4x-5)
Delicious77 [7]

Answer:

2x + 3x^2 (4x - 5)

2x + 12x^3 - 15x^2

12x^3 - 15x^2 + 2x

Degree - 3

Terms - 3 (Trinomial)

<h3>Lets explore more - </h3>

  • The degree of a polynomial is the highest power of its variable
  • Degree represents the no. of zeros of the polynomial

  • <em><u>Linear</u></em><em><u> </u></em> - Degree 1
  • <em><u>Quadrati</u></em><em><u>c</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em>Degree 2
  • <em><u>Cubic</u></em><em><u> </u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em>Degree 3
  • <em><u>Biquadratic</u></em><em><u> </u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em>Degree 4

  • Terms - Classification of polynomial On the basis of terms

  1. monomial - polynomial which has only 1 term
  2. Binomial - Polynomial which has 2 terms
  3. Trinomial - Polynomial which has 3 terms
5 0
3 years ago
Read 2 more answers
Evaluate the expression 263 + 5 when b = 3.<br> 263 +5 = 2(3): +5<br> =
ExtremeBDS [4]

Given:

The expression is:

2b^3+5

To find:

The value of the given expression when b=3.

Solution:

We have,

2b^3+5

Substituting b=3 in the above expression, we get

2b^3+5=2(3)^3+5

2b^3+5=2(27)+5

2b^3+5=54+5

2b^3+5=59

Therefore, the value of given expression at b=3 is 59.

7 0
2 years ago
Read 2 more answers
Identify the zeros of the function f(x) = 4x2 − 8x − 1 using the Quadratic Formula. HELP ASAP!!
forsale [732]

1+\dfrac{\sqrt{5}}{2},1-\dfrac{\sqrt{5}}{2}

Step-by-step explanation:

The given equation is 4x^{2}-8x-1

Let a be the coefficient of x^{2}

Let b be the coefficient of x

Let c be the constant.

Then the roots α,β for the equation ax^{2}+bx+c are \dfrac{-b+\sqrt{b^{2}-4ac} }{2a},\dfrac{-b-\sqrt{b^{2}-4ac} }{2a}

So,α=\frac{-b+\sqrt{b^{2}-4ac} }{2a}=\frac{8+\sqrt{64+16} }{8}=\frac{8+4\sqrt{5}}{8}=1+\frac{\sqrt{5}}{2}

β=\frac{-b-\sqrt{b^{2}-4ac} }{2a}=\frac{8-\sqrt{64+16} }{8}=\frac{8-4\sqrt{5}}{8}=1-\frac{\sqrt{5}}{2}.

So the roots are 1+\frac{\sqrt{5}}{2},1+\frac{\sqrt{5}}{2}

5 0
3 years ago
To solve the equation w/8 - 4 = 20, you would first add 4 to each side and then divide each side by 8.
bearhunter [10]
False because, you DO add 4 to the sides but you would multiply the 8 because you to the opposite to cancel it out

4 0
3 years ago
Read 2 more answers
A square rug has an area of 81 square feet. What is the length of one side of the rug?
Molodets [167]

Answer:

3

Step-by-step explanation:

3*3*3*3=81

that's my answer

5 0
3 years ago
Read 2 more answers
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