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Elina [12.6K]
3 years ago
7

How do you solve 4x+1+7x=13+8x

Mathematics
1 answer:
Alinara [238K]3 years ago
6 0

4x + 1 + 7x = 13 + 8x   Combine like terms

11x + 1 = 13 + 8x  Subtract 8x on both sides

11x + 1 - 8x = 13 + 8x - 8x

3x + 1 = 13  Subtract 1 on both sides

3x + 1 - 1 = 13 - 1

3x = 12   Divide 3 on both sides

x = 4

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Which of the statements is true regarding the graphed functions ?
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4 years ago
Brainliest question please help me answer my question please
OLga [1]

Answer:

Step-by-step explanation:

The area for a trapezoid is

A=\frac{1}{2}h(b_{1}+b_{2})

h is the length of ST, one of the bases is the length of MK, and the other base is the length of AS.  First we'll find h:

The coordinates for S are (0, -2) and T are (1, 2). Using the distance formula:

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d=\sqrt{17}.  So h = √17

Now for the length of MK. The coordinates for M are (-7, 4) and for K (5, 1). Using the distance formula again:

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d=\sqrt{(-12)^2+(3)^2} so

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Now for the length of AS. The coordinates for A: (-4, -1) and for S: (0, -2). Using the distance formula one more time:

d=\sqrt{(-4-0)^2+(-1-(-2))^2} and

d=\sqrt{(-4)^2+(1)^2} and

d=\sqrt{17}. So AS = √17.

Now we can fill in our area formula:

A=\frac{1}{2}(\sqrt{17})(3\sqrt{17}+\sqrt{17})

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5 0
3 years ago
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5 0
3 years ago
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Olenka [21]

Answer:

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we know that

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4 years ago
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