Non so che fare il primo a
You can use any data set in this table (except the row with x) to get the ratio.
so 20/196 is the ratio which equals about .102041
then multiply that decimal by the weight in the x row to see what x is
so 1078(.102041) = 110.000198 just round that to 110. you can also verify that ratio by checking other data points. for instance
490(.102041) = 50.00009 or 50
so you know x is 50 so answer is either b or d
then you know the ratio .102041, so does (10/98) = .102041
or does (98/10) = .102041
if you do the division you will see that (10/98) = .102041
so the answer is D
Answer:
sample mean:: 17.92
ME = z*s/sqrt(n) = 1.8807*6.35/sqrt(47) = 1.7421
------------------------
Step-by-step explanation:
1/3 ln(<em>x</em>) + ln(2) - ln(3) = 3
Recall that
, so
ln(<em>x</em> ¹ʹ³) + ln(2) - ln(3) = 3
Condense the left side by using sum and difference properties of logarithms:


Then
ln(2/3 <em>x</em> ¹ʹ³) = 3
Take the exponential of both sides; that is, write both sides as powers of the constant <em>e</em>. (I'm using exp(<em>x</em>) = <em>e</em> ˣ so I can write it all in one line.)
exp(ln(2/3 <em>x</em> ¹ʹ³)) = exp(3)
Now exp(ln(<em>x</em>)) = <em>x </em>for all <em>x</em>, so this simplifies to
2/3 <em>x</em> ¹ʹ³ = exp(3)
Now solve for <em>x</em>. Multiply both sides by 3/2 :
3/2 × 2/3 <em>x</em> ¹ʹ³ = 3/2 exp(3)
<em>x</em> ¹ʹ³ = 3/2 exp(3)
Raise both sides to the power of 3:
(<em>x</em> ¹ʹ³)³ = (3/2 exp(3))³
<em>x</em> = 3³/2³ exp(3×3)
<em>x</em> = 27/8 exp(9)
which is the same as
<em>x</em> = 27/8 <em>e</em> ⁹