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Misha Larkins [42]
3 years ago
12

Given four functions, which one will have the highest y-intercept?

Mathematics
1 answer:
beks73 [17]3 years ago
6 0
<span>The y-intercept of a function is given by the initial value of a function. It is the value of the function when x = 0.

Given the functions

A. Blake is tracking his savings account with an interest rate of 5% and a original deposit of $6.
The y-intercept for this function is the initial deposit which is $6.

B.
x    g(x)
0    6
1    2
2   10

The y-intersept for this function is 6 which isthe value of the function g(x) when x = 0.


C. The function h of x equals 4 to the x power, plus 3
When x = 0, h(x)=4^0+3=1+3=4
Thus the y-intecept is 4.

D. j(x) = 10(2)^x
when x = 0, j(x)=10(2)^0=10(1)=10
Thus, the y-intercept is 10.

Thereforen the function with the highest y-intercept is j(x)=10(2)^x which has a y-intercept of 10.
</span>
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Answer:

D, 12 is half of 24, and when you put DE to it, it's a little longer than half of 24. So it has to be 18.

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A rational number is such that when you multiply it by 5/2 and add 2/3 to the product, you get 7/12. What is the number?
Afina-wow [57]

Answer:A rational number is such that when you multiply it by 5/2 and add 2/3 to the product you get -7/12 . What is the number.

Step-by-step explanation:Let p/q (q ≠ 0) denote the rational number. Multiplying it by 5/2 gives (p/q)(5/2). Add 2/3 to the product and we get (p/q)(5/2) + 2/3 . The result is given to be -7/12.

∴ (p/q)(5/2) + 2/3 = -7/12 …………………………..……………………………………..(1)

Transposing 2/3 to right-hand-side and changing the sign to negative,

(p/q)(5/2) = -2/3 -7/12 = -(2/3 + 7/12) =- (2 x 4 + 7)/12 (Taking L.C.M.)

Or, (p/q)(5/2) = -(8+7)/12 = - 15/12

Multiplying both sides by 2/5,

(p/q)(5/2) x (2/5) = -15/12 . 2/5 = -(3x5)/(3x4) . 2/5 =- 5/4 .2/5

Since 2/5 is the multiplicative inverse of 5/2, 5/2 x 2/5 = 1 and we obtain

(p/q).1 = -1/4 . 2/1 = -1/2

⇒ p/q = -1/2 which is a negative rational number in which p = 1 and q = 2 ≠ 0 .

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3 0
3 years ago
a shopkeeper had 60 kg apples with him in the morning of a particular day during the day time he could sell only 43 kg 700 gram.
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let c be x2,y2

then apply mid point formula

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