Answer:
5,700,500
Step-by-step explanation:
5.7005 million
5.7005 million
Million is written as 1,000,000
Now:
5.7005million is 5.7005 x 1,000,000
This gives: 5,700,500
Answer
18
Step-by-step explanation: They are skipping -7, 5, -7
A = 1/2 (12x² + 8x + 24x + 16)
A = 1/2 (12x² + 32x + 16)
A = 6x² + 16x + 8
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Answer: 6x² + 16x + 8
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Answer: f(2) = 6
Step-by-step explanation: In this problem, we are given the function
f (x) = (x + 1) 2 and we are asked to find f(2). In other words, if we put an "x" into our function, we get a (x + 1) 2 out.
f we put a 2 into the function, we get f(2) = (2 + 1) 2 out. Now all we have to do is simplify on the right side.
2 + 1 gives us 3 and if we multiply 3 by 2, we get a product of 6.
Therefore, f(2) is 6.
Answer: The mean and standard deviation are 567.2 and 89.88 resp.
Step-by-step explanation:
Since we have given that
For 370 parts per million = 7% = 0.07
For 440 parts per million = 10% = 0.10
For 550 parts per million = 49% = 0.49
For 670 parts per million = 34% = 0.34
So, Mean of the carbon dioxide atmosphere for these trees would be
![E[x]=370\times 0.07+440\times 0.1+550\times 0.49+670\times 0.34=567.2](https://tex.z-dn.net/?f=E%5Bx%5D%3D370%5Ctimes%200.07%2B440%5Ctimes%200.1%2B550%5Ctimes%200.49%2B670%5Ctimes%200.34%3D567.2)
And
![E[x^2]=370^2\times 0.07+440^2\times 0.1+550^2\times 0.49+670^2\times 0.34=329794](https://tex.z-dn.net/?f=E%5Bx%5E2%5D%3D370%5E2%5Ctimes%200.07%2B440%5E2%5Ctimes%200.1%2B550%5E2%5Ctimes%200.49%2B670%5E2%5Ctimes%200.34%3D329794)
So, Variance would be
![Var\ x=E[x^2]-E[x]^2=329794-567.2^2=8078.16](https://tex.z-dn.net/?f=Var%5C%20x%3DE%5Bx%5E2%5D-E%5Bx%5D%5E2%3D329794-567.2%5E2%3D8078.16)
So, the standard deviation would be
Hence, the mean and standard deviation are 567.2 and 89.88 resp.
