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3 years ago

(-5,7) across the x-axis

Mathematics

2 answers:

defon3 years ago

5 0

The answer is -5,-7. Please mark this brainiest.

tresset_1 [31]3 years ago

5 0

The answer is -5,-7 hope this helps you

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Identify the like terms.

Tom [10]

B.
7cd, -12cd

Explanation;
Like terms have similar variables.

3 0

3 years ago

1) 5x + 3 = 23<br> Is the value of x 4

Nataly [62]

Answer:

X = 4

Step-by-step explanation:

5x + 3 = 23

Subtract 3 from both sides: 5x = 20

Divide both sides by 5: x = 4

3 0

3 years ago

H and J are both between G and K such that GH = JK and H is between G and J.

DIA [1.3K]

Answer:

Step-by-step explanation:

So the order of the points is: GHJK

GH = x+10 =JK

HJ=8

JK=2x-4

JK = x+10=2x-4

x+10=2x-4

10+4=2x-x

x=14

GH= 14+10 =24

GJ = GH +HJ = 24+ 8=32

6 0

3 years ago

Help me please thank you

Snezhnost [94]

Point A is at (-5.1 , 3.3)

3 0

4 years ago

A horizontal trough is 16 m long, and its end are isosceles trapezoids with an altitude of 4 m, a lower base of 4 m, and an uppe

Ganezh [65]

Answer:

0.28cm/min

Step-by-step explanation:

Given the horizontal trough whose ends are isosceles trapezoid

Volume of the Trough =Base Area X Height

=Area of the Trapezoid X Height of the Trough (H)

The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)

The Volume of water in the trough at any time

$Volume=\frac{1}{2} (b_{1}+4+2x)h X H$

$Volume=\frac{1}{2} (4+4+2x)h X 16$

=8h(8+2x)

V=64h+16hx

We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles

x/h=1/4

4x=h

x=h/4

Substituting x=h/4 into the Volume, V

$V=64h+16h(\frac{h}{4})$

$V=64h+4h^2\\\frac{dV}{dt}= 64\frac{dh}{dt}+8h \frac{dh}{dt}$

h=3m,

dV/dt=25cm/min=0.25 m/min

$0.25= (64+8*3) \frac{dh}{dt}\\0.25=88\frac{dh}{dt}\\\frac{dh}{dt}=\frac{0.25}{88}$

=0.002841m/min =0.28cm/min

The rate is the water being drawn from the trough is 0.28cm/min.

3 0

4 years ago