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insens350 [35]
4 years ago
13

How do I solve radicals??

Mathematics
1 answer:
Sav [38]4 years ago
4 0
Your question is too general.  You might ask instead, "how do I simplify the radical sqrt(48)?"

sqrt(48) can b e simplified by rewriting 48 as the product of the perfect square 16 and the not-a-perfect-square 3:

sqrt(48) = sqrt(16)*sqrt(3) = 4*sqrt(3)    (answer)

In #76, rearrange the terms so that you have 3sqrt(7x+4)=15.  Then divide both sides by 3, obtaining sqrt(7x+4) =5.  Squaring both sides:  7x+4=25.
Solve this linear equation for x.
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Find the zero(s) of each function algebraically.<br>f(x) = 8x-16<br>​
vodomira [7]

the zero(s) of function  f(x)=8x-16 is x=2

Step-by-step explanation:

We need to find the zero(s) of function algebraically.

We are given: f(x)=8x-16

To find the zeros we put the function equal to zero.

8x-16=0\\Solving:\\8x=16\\x=\frac{16}{8}\\x=2

So, the zero(s) of function  f(x)=8x-16 is x=2

Keywords: zero(s) of function

Learn more about zero(s) of function at:

  • brainly.com/question/1414350
  • brainly.com/question/1464739
  • brainly.com/question/2568692

#learnwithBrainly

4 0
3 years ago
The volume of a sphere is increased by 6%. Calculate the corresponding percentage increased in it area.
lions [1.4K]

Answer:

The new volume will be V + 0.06V or 1.06V

Step-by-step explanation:

The volume of the sphere increased by 6% or 0.06V. This means the total volume of the sphere will be V + 0.06V or 1.06V.


3 0
4 years ago
E=6c^2-2c-1<br> F=-4c^2+7c+5<br> E+F=
kifflom [539]

Answer:

E + F =   2c^2  + 5c + 4

Step-by-step explanation:

E=6c^2-2c-1

F=-4c^2+7c+5

E+F=  6c^2   -2c   -1  +  -4c^2   +   7c   +  5

E + F =   6c^2 - 4c^2  - 2c + 7c  - 1  + 5

E + F =   2c^2  + 5c + 4

4 0
3 years ago
Independent Practice
Sedbober [7]

Answer: THE ANSWER IS D. (-27, -7, -2, 8, 48)

Step-by-step explanation:

Graph.

y = 5 x − 2

{ − 5 ,  − 1 ,  0 ,  2 ,  10 }

The chosen topic is not meant for use with this type of problem. Try the examples below.

1  ,  2  ,  2  ,  2  ,  3  ,  4  ,  4  ,  5  ,  8  ,  9  ,  10

11  ,  14  ,  14  ,  17  ,  17  ,  17  ,  41  ,  44  ,  47  ,  71  ,  74  ,  77

12  ,  15  ,  45  ,  65  ,  78

5 0
3 years ago
What are the solutions of 3(x-4)(2x-3)=0
dexar [7]
3(x-4)(2x-3)=0
(x-4)(2x-3)=0
x=4
x=3/2
7 0
4 years ago
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