Ask question

Ask question

All categories

3 years ago

9

PLEASE HELP?

1 answer:

AlekseyPX3 years ago

6 0

I think you forgot to give the diagram along with the question. I am answering the question based on my research and knowledge. "x = 7, y = 9" is the one among the following choices given in the question that gives the value of "x" and "y". The correct option among all the options that are given in the question is the third option or option "C".

You might be interested in

In one poem, which "poor and country-bred" figure is said to have caused smart people to "laugh at him" and ask, "How can so ver

Kay [80]

Abraham Lincoln, i've read that story a long time ago myself and I remember who said that.

6 0

3 years ago

A girl weighs 5/8 as much as her brother does. If the girl weighs 110 lb, how much does her brother weigh?

fomenos

Brother's weight * 5/8 = 110
Brother's weight * 5/8÷5/8 = 110÷ 5/8
Brother's weight = 176

7 0

3 years ago

Read 2 more answers

Three divided by four

muminat

Answer:

0.75

Step-by-step explanation:

3/4=0.75

Hope this helps! :)

8 0

3 years ago

Find the f^-1(x) and it’s domain

borishaifa [10]

Answer:

$f^{-1}(x) = (x + 8)^2$

$x \ge -8$

Step-by-step explanation:

Given

$f(x) = \sqrt x - 8$

Solving (a): $f^{-1}(x)$

We have:

$f(x) = \sqrt x - 8$

Express f(x) as y

$y = \sqrt x - 8$

Swap x and y

$x = \sqrt y - 8$

Add 8 to $both\ sides$

$x + 8 = \sqrt y - 8 + 8$

$x + 8 = \sqrt y$

Square both sides

$(x + 8)^2 = y$

Rewrite as:

$y = (x + 8)^2$

Express y as: $f^{-1}(x)$

$f^{-1}(x) = (x + 8)^2$

To determine the domain, we have:

The original function is $f(x) = \sqrt x - 8$

The range of this is: $f(x) \ge -8$

The $domain$ of the $inverse$ function is the $range$ of the $original$ function.

<em>Hence, the domain is:</em>

$x \ge -8$

3 0

3 years ago

What is the growth factor of the exponential function

Deffense [45]

Answer:

the answer is 5

Step-by-step explanation:

4 0

3 years ago