Answer:
Mean=2.53
median=2
mode=2
range=3
Step-by-step explanation:
1, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 4
MEAN
Add up all data values to get the sum
Count the number of values in your data set
Divide the sum by the count
38/15=2.53
MEDIAN
Arrange data values from lowest to the highest value
The median is the data value in the middle of the set
If there are 2 data values in the middle the median is the mean of those 2 values.
MODE
Mode is the value or values in the data set that occur most frequently.
RANGE
18-15=3
First picture)
I: 5x+2y=-4
II: -3x+2y=12
add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
x=-2
insert x=-2 into I:
5*(-2)+2y=-4
-10+2y=-4
2y=6
y=3
(-2,3)
question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
33-adults=childs
insert childs into I:
115=3*(33-adults)+5*adults
115=99-3*adults+5*adults
16=2*adults
8=adults
insert adults into II:
33-8=childs
25=childs
so it's the last option
question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
b) y>6 and y>2 can also be written as 2<6<y, so solution 7 exist for example
c) y<6 and y<2 inverse of b: y<2<6, so for example 1
d) y>6 and y<2: y<2<6<y, this is impossible as y can be only either bigger or smaller than 2 or 6
so it's the last option
question 8)
I: x+y=12
II: x-y=6
subtract: I-II:
x+y-(x-y)=12-6
2y=6
y=3
insert y into I:
x+3=12
x=9
(9,3)
question 9)
I: x+y=6
II: x=y+5
if you take the x=y+5 definition of II and substitute it into I:
(y+5)+y=6
which is the second option :)
18.90? I believe would be the answer . Let's see if someone else responds
The expression to solve is the
300-7 [4 (3+5)] + 3 to the 3rd power
3 to the third power means 3³, so
300-7 [4(3+5)]+3³
= 300 - 7 [4(8)] + 27
= 300 - 7[32] + 27
= 300 - 224 + 27
= 76 + 27
= 103
so, by solving this we get 103
Answer:
-12
Step-by-step explanation:
-4-(5+3)
-4-(8)
-4-8
-12
