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nignag [31]
3 years ago
9

Graph the exponential function

ula1" title=" f(x)=\frac{1}{2}^{x} " alt=" f(x)=\frac{1}{2}^{x} " align="absmiddle" class="latex-formula"> .

Mathematics
1 answer:
tatyana61 [14]3 years ago
3 0

f(x)=\left(\dfrac{1}{2}\right)^x\\\\for\ x=-3\to y=\left(\dfrac{1}{2}\right)^{-3}=2^3=8\to(-3,\ 8)\\\\for\ x=-2\to y=\left(\dfrac{1}{2}\right)^{-2}=2^2=4\to(-2,\ 4)\\\\for\ x=-1\to y=\left(\dfrac{1}{2}\right)^{-1}=2^1=2\to(-1,\ 2)\\\\for\ x=0\to y=\left(\dfrac{1}{2}\right)^0=1\to(0,\ 1)\\\\for\ x=1\to y=\left(\dfrac{1}{2}\right)^1=\dfrac{1}{2}\to\left(1,\ \dfrac{1}{2}\right)\\\\for\ x=2\to y=\left(\dfrac{1}{2}\right)^2=\dfrac{1}{4}

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10x +1 12x-5 solve for x
dimulka [17.4K]

Answer:

x = 3

Step-by-step explanation:

10x + 1 = 12x - 5

Subtract 1 from each side

10x = 12x - 6

Subtract 12x from each side

-2x = -6

Divided by -2

x = 3

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How many times does seven go into three hundred ninety four
Nookie1986 [14]

Answer: 56 times.

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394/7 = 56.3

56 * 7 = 392

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399 is more than 394, therefore the answer is 56.

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An animal feed to be mixed from soybean meal and oats must contain at least 168 lb of protein, 27 lb of fat, and 14 lb of minera
atroni [7]

Answer:

The animal farm should buy 1.775 bags of soybeans and 1.575 bags of oats

Cost = 51.275

Step-by-step explanation:

The given parameters can be summarized as:

\begin{array}{cccc}{} & {x} & {y} & {Total} & {Protein} & {70} & {21} & {168} &{Fats}& {9} & {7} & {27} & {Minerals} & {7} & {1} & {14}& {Cost} & {21} & {7} & {} \ \end{array}

Where: x = Soybeans and y = Oats.

So, the system of equations are:

70x + 21y = 168

9x +7y = 27

7x + y = 14

Cost = 21x + 7y

The best way to solve this, is using graph

Plot the following equations on a graph, and get the points of intersection:

70x + 21y = 168

9x +7y = 27

7x + y = 14

From the attached graph, we have:

(x_1,y_1) = (1.636,2.545)

(x_2,y_2) = (1.775,1.575)

(x_3,y_3) = (2.023,1.256)

Substitute each of the values of x's and y's in the cost function to get the minimum cost:

Cost = 21x + 7y

(x_1,y_1) = (1.636,2.545)

Cost = 21 * 1.636 + 7 * 2.545

Cost = 52.171

(x_2,y_2) = (1.775,1.575)

Cost = 21 * 1.775 + 7 * 1.575

Cost = 48.3

(x_3,y_3) = (2.023,1.256)

Cost = 21 * 2.023 + 7 * 1.256

Cost = 51.275

The values of x and y that gives the minimum cost is:

(x_2,y_2) = (1.775,1.575)

and the minimum cost is:

Cost = 48.3

Hence, the animal farm should buy 1.775 bags of soybeans and 1.575 bags of oats

5 0
3 years ago
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