Because the common cold is cause by a ‘virus’.......
The answer is VIRUS
<u>Answer</u>: Option D. RNA polymerase.
<u>Explanation</u>:
- Transcription is the process which is used to produce RNA from a DNA template.
- The enzyme involved in the process of transcription is <em>RNA</em> <em>polymerase</em> which is responsible for separating the DNA strands and making an RNA which is complementary to the DNA.
- RNA polymerase joins the nucleotides in the newly formed RNA strands by utilizing the energy released from the cleavage of the additional phosphate bonds that are removed by it.
- The RNA polymerase dissociates from the DNA only after the process of transcription is complete.
Attached is an image with the correct labeling.
Https://s-media-cache-ak0.pinimg.com/564x/5f/38/fc/5f38fc3ce20c9b6deb0613f73c82e03a.jpg
Here is a image. Hope this helps :)
Genetics, blood type gene has two alleles, each allele has genotype A, B or O. The A and B are dominant, and O is recessive. So allele A combined with allele O is type A. Similarly, BO is type B, AA is type A, BB is type B, OO is type O, and AB is typeAB.
If both parents have type A blood, then the alleles could be AA or AO, thus the allele A frequency is 75%, allele O frequency is 25% for both parents.
So the chance of alleles OO is 25% × 25% = 6.25%,
alleles AA is 75% × 75% = 56.25%,
alleles AO is 75% × 25% = 18.75%,
alleles OA is 25% × 75% = 18.75%.
Since AA, AO and OA are blood type A, and OO is blood type O, thus their child has 6.25% chance to be blood type O and 93.75% chance to be blood type A.
The +/- is called the rhesus factor, with + being dominant, and - being recessive.
So if both parents are -, the kids are always -, otherwise the kids might be + or -.
Child Blood Type Estimate Table:
Father's Blood TypeABABOMother's
Blood
TypeAA/OA/B/AB/OA/B/ABA/OBA/B/AB/OB/OA/B/ABB/OABA/B/ABA/B/ABA/B/
Answer:
c. AATGGAGTT
d. AATAGAGTC
Explanation:
SNP is a single nucleotide polymorphism. It means that a particular sequence varies among the members of a population with respect to the single nucleotide. The given sequence of the human genome is "AATGGAGTC". The sequence "AATGGAGTT" of option C differs from it with respect to the single nucleotide at the last position (C is replaced with T).
Similarly, the sequence of option D "AATAGAGTC" differs with respect to the nucleotide at position 4 (G in the original sequence is replaced with A). Therefore, these two sequences represent SNP with respect to the given sequence of the human genome.
