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3 years ago

Please can you help me on me question posted a picture

Mathematics

2 answers:

ladessa [460]3 years ago

6 0

For this case we have the following expression:
y = (x + 3) ^ 2 + 53
We rewrite the expression:
y = (x ^ 2 + 6x + 9) + 53
We add the constant term:
y = x ^ 2 + 6x + 62
Answer:
The standard equation of the polynomial for this case is given by:
y = x ^ 2 + 6x + 62
option B

tia_tia [17]3 years ago

5 0

I am 99% sure it is D. Hope this helped! : )

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There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In

Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the sampling distribution of the sampling proportions.

The mean and standard deviation of this sampling distribution is:

$\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}$

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

$P(0.45$

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

$z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)$

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

$P(p>0.8)=P(z>z^*)$

The z value is calculated as before:

$z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0$

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0

2 years ago

Please help and thank you

tresset_1 [31]

Answer:

A. The description represents an arithmetic sequence because the successive y-values have a common difference of 600

Step-by-step explanation:

The equation that this situation is describing would be

$y=600x+20000$

This would mean that this equation would be an arithmetic series

5 0

3 years ago

There are 200 students in an eleventh-grade high school class. There are 40 students in the soccer team and 50 students in the b

Dvinal [7]

Answer:

1/5,1/4,1/20, yes, yes

Step-by-step explanation:

3 0

3 years ago

Find the zeros of x3 +2X^2-23x-60

laila [671]

Hello,

P(x)=x^3+2x²-23x-60
P(-4)=(-4)^3+2*(-4)²-23*(-4)-60=0
P(-3)=(-3)^4+2*(-3)²-23*(-3)-60=0
P(5)=5^3+2*5²-23*5-60=0
Zeros are -4,-3,5

5 0

2 years ago

Help out?? Mathematics image.

Brilliant_brown [7]

Answer: (12) ∠1 = 20° (13) ∠2 = 50° (14) ∠3 = 15° (15) UV = 80° (16) AB = 40° (17) ABC or 180° - CD (18) BC - 140° (19) ABC = 150°

Step-by-step explanation:

12) $\frac{1}{2}$ (UV - ST) = ∠1

$\frac{1}{2}$ (80 - 40) = ∠1

$\frac{1}{2}$ (40) = ∠1

20 = ∠1

13) $\frac{1}{2}$ (UV + ST) = ∠2

$\frac{1}{2}$ (70 + 30) = ∠2

$\frac{1}{2}$ (100) = ∠2

50 = ∠2

14) $\frac{1}{2}$ (VB - BS) = ∠3

$\frac{1}{2}$ (60 - 30) = ∠3

$\frac{1}{2}$ (30) = ∠3

15 = ∠3

15) $\frac{1}{2}$ (UV - ST) = ∠1

$\frac{1}{2}$ (UV - 20) = 30

UV - 20 = 60

UV = 80

16) ∠1 = arc AB

∠1 = 40

arc AB = 40

17) arc AB + arc BC = arc AC

= 180 = arc CD

18) ∠1 + ∠2 + ∠3 = 180

20 + ∠2 + 20 = 180

∠2 + 40 = 180

∠2 = 140

19) ∠1 + ∠ 2 = arc ABC

∠1 + ∠2 + ∠3 = 180

arc ABC + 30 = 180

arc ABC = 150

4 0

3 years ago