Y = x² - 4x + 4
y = 2x - 4
Find intersection of L and C:
x² - 4x + 4 = 2x - 4
x² - 6x + 8 = 0
<span> (x - 2)(x - 4) = 0
x = 2 or x = 4
When x = 2 , y = 2(2) - 4 = 0
When x = 4, y = 2(4) - 4 = 4
Points of intersection = A(2, 0) and B(4, 4)
Find the length of AB:
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![ \text {Length of AB}= \sqrt{(4-0)^2 + (4-2)^2} = \sqrt{16 + 4} = \sqrt{20} = 4.47 \text{ units}](https://tex.z-dn.net/?f=%0A%5Ctext%20%7BLength%20of%20AB%7D%3D%20%20%5Csqrt%7B%284-0%29%5E2%20%2B%20%284-2%29%5E2%7D%20%3D%20%20%5Csqrt%7B16%20%2B%204%7D%20%3D%20%5Csqrt%7B20%7D%20%20%3D%204.47%20%5Ctext%7B%20units%7D)
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Answer: 4.47 units</span>
Answer:
C
15 + x
Step by step explanation
For Company X, the initial cost is 30 cents plus 5 cents per minute, so the expression would be 30 + 5x (x would represent minutes.
For Company Y, the initial cost is 15 cents plus 4 cents per minute, so the expression would be 15 + 4x (x would represent minutes.)
Then subtract the expression of Y from the expression of X to show the difference in value between Y and X.
So, 30 + 5x - (15 +4x)
Distribute the subtraction sign.
30 + 5x - 15 - 4x
Solve across.
15 + x
Answer:
length = x - 2
Step-by-step explanation:
Area (A) of rectangle = lw ( l is the length and w the width )
A = x² - 7x + 10 = (x - 2)(x - 5) ← in factored form
l =
= ![\frac{(x-2)(x-5)}{x-5}](https://tex.z-dn.net/?f=%5Cfrac%7B%28x-2%29%28x-5%29%7D%7Bx-5%7D)
cancel the factor (x - 5) on the numerator/ denominator, hence
l = x - 2
Answer$67
Step-by-step explanation:
<span>C) The triangles could have the same shape but not necessarily the same size.
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