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Brrunno [24]
3 years ago
13

Solve the equation

Mathematics
2 answers:
Alborosie3 years ago
7 0
C. There is no solution.

6(x+4)=5(x-5)+x
6x+24=5x-25+x
6x+24=6x-25
24=-25
The statement is false for any value of x
∴ There is no solution.

Hope my answer helped u :)
WARRIOR [948]3 years ago
6 0

Answer:

➣ C. There is no solution

Step-by-step explanation:

6\left(x+4\right)=5\left(x-5\right)+x

<u>Apply distributive law:-</u>

=6x+6\cdot \:4

<u>➠ Now, Multiply:- 6 × 4= 24</u>

6x+24

5\left(x-5\right)+x

=5x-25

=5x-25+x

<u>➠ Group like terms:-</u>

=6x-25

Now, we have...

6x+24=6x-25

<u>➠ Subtract 24 from both sides:-</u>

6x+24-24=6x-25-24

6x=6x-49

<u>➠ Now, Subtract 6x from both sides:- </u>

6x-6x=6x-49-6x

0=-49

Here, the sides are not equal so there is <u>no Solution</u>

<u>OAmalOHopeO</u>

✎.......................

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Answer:

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Steps to solve:

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A contractor developed a multiplicative time-series model to forecast the number of contracts in future quarters, using quarterl
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There is a missing content in the question.

After the statements and before the the options given; there is an omitted content which says:

Referring to Table 16-5, in testing the coefficient of X in the regression equation (0.117) the results were a t-statistic of 9.08 and an associated p-value of 0.0000. Which of the following is the best interpretation of this result?

Answer:

C. The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05).

Step-by-step explanation:

From the given question:

The resulting regression equation can be represented as:

\hat Y = 3.37 + 0.117 X - 0.083 Q_1 + 1.28 Q_2 + 0.617Q_3

where;

the estimated number of contracts in a quarter X is the coded quarterly value with X = 0

the first quarter of 2010 Q1 is a dummy variable equal to 1 in the first quarter of a year and 0 otherwise

Q2 is a dummy variable equal to 1 in the second quarter of a year and 0 otherwise

Q3 is a dummy variable equal to 1 in the third quarter of a year and 0 otherwise

Our null and alternative hypothesis can be stated as;

Null hypothesis :

H_0 :  The quarterly growth rate in the number of contracts is not  significantly different from 0% (? = 0.05)

H_a:  The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

The decision rule is to reject the null hypothesis if the p-value is less than 0.05.

From the missing omitted part we added above; we can see that the   t-statistics value = 9.08 and the p-value = 0.000 .

Conclusion:

Thus; we reject the null hypothesis and accept the alternative hypothesis. i.e

The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

4 0
3 years ago
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