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KiRa [710]
3 years ago
9

#4- A baby weighed 7.6 pounds at birth and 9 1/2 pounds after 6 Weeks. What was the percent increase?

Mathematics
1 answer:
ivanzaharov [21]3 years ago
3 0
The pounds increased 1.6 hope this helped
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Statisticians prefer large samples. Describe briefly the effect of increasing the size of a sample (or the number of subjects in
Flauer [41]

Answer:

Margin of Error decreases

Pvalue decreases

Power increases

Step-by-step explanation:

The margin of error decreases as sample size increases given the same level of confidence, hence, the interval gets narrower.

The margin of error = (Zcritical * σ/√n) ; where, n is the denominator, as the denomination increases, the obtained value will decrease, hence, the margin of error.

When we have a false H0, then we expect a statistical result which will reject H0, with all facts remaining unchanged , increase in sample size n, will lead to decrease in Pvalue, because a lower P value increases the significance of statistical test needed to reject H0.

The power of a fixed level test when the null hypothesis is true, higher power is required to reject the null , increasing n will increase the probability of rejecting H0, by increasing the power of a fixed level test.

8 0
2 years ago
Find the sum 7/8 + 2/4
sdas [7]

Answer:

1.375

Step-by-step explanation:


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3 years ago
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zhuklara [117]

Answer:it should be b!

Step-by-step explanation:

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4 0
2 years ago
Which relationships describe the angle pair x° and 50°
worty [1.4K]

Answer:

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Step-by-step explanation:

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Find the common ratio for the geometric sequence defined by the formula: an=40(2‾√)n−1 a n = 40 ( 2 ) n − 1
WITCHER [35]

The ratio of the geometric sequence 402^{n-1} is 2.

Given that geometric sequence is 40*2^{n-1} and we have to find the common ratio of all the terms.

Geometric sequence is a sequence in which all the terms have a common ratio.

Nth termof a GP is ar^{n-1} in which a is first term and r is common ratio.

Geometric sequence=40*2^{n-1}

We have to first find the first term, second term and third term of a geometric progression.

First term=40*2^{1-1}

=40*2^{0}

=40*1

=40

Second term=40*2^{2-1}

=40*2^{1}

=40*2

=80

Third term=40*2^{3-1}

=40*2^{2}

=40*4

=160

Ratio of first two terms=80/40=2

Ratio of next two terms=160/80=2

Hence the common ratio of geometric sequence is 2.

Learn more about geometric progression at brainly.com/question/12006112

#SPJ1

4 0
2 years ago
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