There are different ways to solve a quadratic equation, the main ones that i'm thinking about right now are:
1) factor the equation as a product:
ex: x^2+ 4x + 3 =0
(x+3) (x+1) = 0
x=-3 and x=-1 are the solutions.
To find (x+p) and (x+q) you have to think that (p+q )have to be equal to the number that is multiplied by x, in my example it was 4 (3+1=4), (p times q) have to be equal to the last number of the quadratic equation, the one that is not multiplied by any x, that in my example is 3 (3 x 1= 3)
2) The other way to solve a quadratic function is by using a formula:
given: ax^2 +bx +c=0
x= (-b +/- <span>√(b^2 -</span> 4ac)) / 2a
ex: 3x^2 + 4x -2=0
x= (-4 +/- √16-4(3)(-2)) / 6= (-4 +/- √16+24)/6= (-4 +/- <span>√40) / 6
now there are 2 possibilities: x= (-4+</span><span>√40) /6
and
x= (-4 - </span><span>√40) / 6
I hope the examples were clear enough also if i did't get very nice numbers. Look closely to the sings + and -, they are very important</span>
12,089 is less than 12,098
The first choice is the correct one.
To determine the inverse of a function, we first write the parent function in terms of y. So, in this part the x would be isolated to one side of the equation. Then, with the new form of the parent function, we switch the x into y and y to x. The new function would be the inverse function. For the given function, we do as follows:
<span> y=-4/x + 1
y - 1 = -4/x
x ( y - 1 ) = -4
x = -4 / (y -1)
Replacing x into y and y into x,
</span>y = -4 / (x -1)
<span>Therefore, the inverse is y=-a/x-b where a = 4 and b = 1.</span>
Answer:
c=256
Step-by-step explanation:
m²+32m+c=m²+32m+(32/2)²-(32/2)²+c
=m²+32m+16²-16²+c
=(m+16)²-256+c
for it to be a complete square -256+c=0
or c=256
