Write an equation for a direct variation that includes the point (2,-6)
2 answers:
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Answer:
- slope = 3/2
- y-intercept = 3
- x-intercept = -2
Step-by-step explanation:
The slope is the coefficient of x when the equation is of the form ...
y = (something).
Here, we can put the equation in that form by subtracting 12x and dividing by the coefficient of y:
12x -8y = -24 . . . . . given
-8y = -12x -24 . . . . .subtract 12x
y = 3/2x +3 . . . . . . . divide by -8
This is the "slope-intercept" form of the equation. Generically, it is written ...
y = mx + b . . . . . . where m is the slope and b is the y-intercept
So, the above equation answers two of your questions:
slope = 3/2
y-intercept = 3
__
The x-intercept is found fairly easily from the original equation by setting y=0:
12x = -24
x = -24/12 = -2 . . . . . the x-intercept
_____
A graph of the equation can also show you these things. The graph shows a rise of 3 units for a run of 2, so the slope is rise/run = 3/2. The line crosses the axes at x=-2 and y=3, the intercepts.
0.542=0.500 + 0.040+0.002
=
=5 tenth + 4 hundredths + two thousandths
One tenth =
One Hundredth=
One thousandth=
Answer:
D: {(-5, -4, 2, 2, 5)}
R: {(-6, 3, 4, 1, 5)}
The relation is NOT a function.
Step-by-step explanation:
By definition:
A relation is any set of ordered pairs, which can be thought of as (input, output).
A function is a <em><u>relation</u></em> in which no two ordered pairs have the same first component (domain/input/x value) and different second components (range/output/y value).
Looking at the given points in your graph, and in listing down the domain and range, we can infer that the relation is not a function because there is an x-value (2) that has two corresponding y-values: (2, 4) (2, 1).
Another way to tell if a given set of points in a graph represents a function by doing the "Vertical line test." The graph of an equation represents y as a function of x if and only if no vertical line intersects the graph more than once. Looking at the attached image, I drew a vertical line over points (2, 4) (2, 1). The vertical line intersects the two points, which fails the vertical line test. This is an indication that the given relation is not a function.
