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Rashid [163]
3 years ago
10

Write an equation for a direct variation that includes the point (2,-6)

Mathematics
2 answers:
igomit [66]3 years ago
8 0
Y = -3x
hope it helps


work: -6 divided by 2 is -3, therefore y = -3x
notka56 [123]3 years ago
6 0

The is Answer: y=-3x

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What is the simplified value of the expression below?
Y_Kistochka [10]

Answer:

-78.12

Step-by-step explanation:

6 0
3 years ago
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Yumiko solved |x|>5 by solving x>-5 and x<5. explain the error yumiko made
Whitepunk [10]

Answer:

switched signs around

Step-by-step explanation:

I believe that s/he switched the signs around so

|x|>5 is solved by x<-5 and x>5

but I'm not quite sure, sorry

3 0
2 years ago
At the green house of salad you get a $1 coupons for every 3 salads you buy.What is the least number of salad you could buy to g
IrinaK [193]

If one coupons costs you 3 salads, 10 salads costs you 10 × 3 = 30 salads.

To get $10 in coupons, the least amount of salads you would need to buy is 30.

5 0
3 years ago
Solve my question please, I’ll mark u as brainlest if the answer is correct and if you solved my question!!!
ikadub [295]

Answer:

x = price of balcony tickets = $7

y = price of orchestra tickets = $21

Step-by-step explanation:

Let

x = price of balcony tickets

y = price of orchestra tickets

y = 3x (1)

148y + 76x = 3,640 (2)

Substitute y = 3x into (2)

148y + 76x = 3,640 (2)

148(3x) + 76x = 3,640

444x + 76x = 3,640

520x = 3,640

x = 3,640/520

x = 7

Substitute x = 7 into (1)

y = 3x (1)

y = 3(7)

y = 21

x = price of balcony tickets = $7

y = price of orchestra tickets = $21

3 0
2 years ago
Mike just hopped on the edge of a merry-go-round. What are his linear and angular speeds if the diameter of the merry-go-round i
dsp73

Step-by-step explanation:

Given that,

The diameter of the merry-go-round, d = 14 feet

Time taken, t = 6 seconds

Radius, r = 7 feet

The linear speed of the merry-go-round is given by :

v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 7}{6}\\\\=7.33\ m/s

Also,

v=r\omega

Where

\omega is the angular speed

So,

\omega=\dfrac{v}{r}\\\\\omega=\dfrac{7.33}{7}\\\\=1.04\ rad/s

Hence, his linear and angular speeds are 7.33 m/s and 1.04 rad/s.

8 0
3 years ago
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