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3 years ago

Write an equation for a direct variation that includes the point (2,-6)

Mathematics

2 answers:

igomit [66]3 years ago

8 0

Y = -3x
hope it helps

work: -6 divided by 2 is -3, therefore y = -3x

notka56 [123]3 years ago

6 0

The is Answer: y=-3x

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I need help with this problem

katrin [286]

9514 1404 393

Answer:

(d) y = -2x +8

Step-by-step explanation:

The parallel line will have the same x-coefficient, eliminating choices B and C. If it goes through point (4, 0), then (x, y) = (4, 0) will satisfy the equation.

A: 0 = -2(4) +4 = -4 . . . . . not true

D: 0 = -2(4) +8 . . . . . . . . true

The equation you're looking for is ...

y = -2x +8

<em>Additional comment</em>

Since you know the slope is -2 and a point on the line is (4, 0), you can use the point-slope form of the equation for a line as a starting point.

y -k = m(x -h) . . . . . . line with slope m through point (h, k)

For m = -2, and (h, k) = (4, 0), the equation becomes ...

y -0 = -2(x -4)

Simplified to slope-intercept form, this is ...

y = -2x +8

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3 years ago

A rock dropped on the moon will increase its speed from 0 m/s (its starting

belka [17]

<h2>Hello!</h2>

The answer is:

The correct option is the option D

$g=1.63\frac{m}{s^{2}}$

To calculate the acceleration, we need to use the following formula that involves the given information (initial speed, final speed, and time).

We need to use the following free fall equation:

$V_{f}=V_{o}-g*t$

Where:

$V_{f}$ is the final speed.

$V_{o}$ is the initial speed.

g is the acceleration due to gravity.

t is the time.

We are given the following information:

$V_{f}=8.15\frac{m}{s}$

$V_{o}=0\frac{m}{s}$

$t=5seconds$

Then, using the formula to isolate the acceleration, we have:

$V_{f}=V_{o}-g*t$

$V_{f}=V_{o}-g*t\\\\g*t=V_{o}-V_{f}\\\\g=\frac{V_{o}-V_{f}}{t}$

Now, substituting we have:

$g=\frac{V_{o}-V_{f}}{t}$

$g=\frac{0-8.15\frac{m}{s}}{5seconds}=-1.63\frac{m}{s^{2}}$

Therefore, since we are looking for a magnitude, we have that the obtained value will be positive, so:

$g=1.63\frac{m}{s^{2}}$

Hence, the correct option is the option D

$g=1.63\frac{m}{s^{2}}$

Have a nice day!

7 0

3 years ago