Answer:
Step-by-step explanation:
Any polynomial will have degrees of variable in integers and the degrees would be always positive.
It is conventional to write standard forms of polynomials in the descending powers of x.
i.e. we write for cubic polynomial the term containing x cube, and for power 5 polynomial, the term containing power 4, next power 3, thus strictly in descending order.
The given polynomial is
This is a polynomial because all x have powers in positive integers.
But this is not in standard form as highest degree of 4 is not the first term
Let us rearrange according to powers of m
We get
as standard form
The answer is: 90 you can calculate this: 900/10=90
Answer:
y= -5/2x -1
Step-by-step explanation:
Answer:
−5c5−15a−25b+10
Step-by-step explanation:
13+2−5−15a−25b−5c5
=13+2+−5+−15a+−25b+−5c5
Combine Like Terms:
=13+2+−5+−15a+−25b+−5c5
=(−5c5)+(−15a)+(−25b)+(13+2+−5)
=−5c5+−15a+−25b+10
Answer:
=−5c5−15a−25b+10
h(x) = x g(x)
h'(x) = x g'(x) + (1)g(x)
h'(x) = x g'(x) + g(x)
Since g(x) = f^-1(x), then
g'(x) = 1/f'(x)
h'(x) = x/f'(x) + f^-1(x)
Therefore,
h'(5) = 5/f'(5) + f^-1(5).
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