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Wittaler [7]
3 years ago
6

TV show information can either keep track of the number of viewers per show or the name of a show. Information is kept in a file

(see sample files below). If the first line of the file says Show, we should store the names of the shows. If the first line of the file says Viewer, we should store the number of viewers per show.
Create a class to complete the program below.
int main(int argc, char** argv) Tv_show_info Tv_show_info show_names(argv[2]);
int n=viewers.info.at(0);
std::string s=show_names.info.at(0);

Sample input file 2: Viewer Sample input file 1: Show Stranger Things Game of Thrones Black Mirror 34 100

its not provided, we are to recreate it. but this is what i made..

template
class Tv_show_info
{
public:
// template
Tv_show_info(string & file):
filename{file}
{
ifstream myfile {filename};
vectorinfo;
T lines;
while (getline(myfile,lines))
{
info.push_back(lines);
}
}
private:
string filename;
};

Computers and Technology
1 answer:
Elza [17]3 years ago
3 0

Answer:

See explaination for Program source code.

Explanation:

The program source code below.

#include <iostream>

#include <fstream>

#include <vector>

using namespace std;

class Show

{

private:

string title;

int viewers;

public:

Show()

{

this->title = "";

this->viewers = 0;

}

Show(string title, int viewers)

{

this->title = title;

this->viewers = viewers;

}

string getTitle(){ return this->title; }

int getViewers(){ return this->viewers; }

};

int main()

{

vector<Show> shows;

vector<string> titles;

vector<int> viewers;

ifstream inFile1("file1.txt");

ifstream inFile2("file2.txt");

string line1, line2;

if(!inFile1.is_open() || !inFile2.is_open())

{

cout << "Either of the files could not be found!\n";

exit(0);

}

getline(inFile1, line1);

if(line1.compare("Show") == 0)

{

while(getline(inFile1, line1))

{

titles.push_back(line1);

}

inFile1.close();

}

getline(inFile2, line2);

if(line2.compare("Viewer") == 0)

{

while(getline(inFile2, line2))

{

viewers.push_back(stod(line2));

}

inFile2.close();

}

for(int i = 0; i < titles.size(); i++)

{

shows.push_back(Show(titles[i], viewers[i]));

}

// display all the show details

cout << "\nALL SHOWS:\n----------\n";

for(Show show : shows)

{

cout << "Title: " << show.getTitle() << ", Number of viewers: " << show.getViewers() << endl;

}

cout << endl;

return 0;

}

See attachment for output

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Answer:

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a) True

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Answer:

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The function below takes two arguments: a dictionary of strings (keys) to integers (values) a_dict and a list of strings key_lis
vitfil [10]

Answer:

  1. def getData(a_dict, key_list):
  2.    result = []
  3.    for key in key_list:
  4.        result.append(a_dict[key])
  5.    
  6.    return result  
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Explanation:

Let's define a function <em>getData() </em>with two parameters,<em> a_dict </em>and <em>key_list</em> as required by the question (Line 1).

Since the function is to return a list of associated values of dictionaries, a new list,<em> result</em>,  is declared and initialized with empty values (Line 2).

Next, use for-loop to traverse through every string in the input <em>key_list </em>(Line 4) and use the traversed key to address the value in the<em> a_dict </em>and add it to the <em>result</em> list (Line 5)

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We can test the function using the test case from the question and we shall see the output as follows:

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