Sin (tan^(-1)X)
Sin (1/tan X)
Sin (1/1 / tan X/1)
Tan X = sin X/cos X
Sin (1/1 / sin X/cos X)
Sin (1/1 • cos X/Sin X)
Sin (cos X/sin X )
Cos X.
I believe the correct answer is cos X.
Answer:
52°
Step-by-step explanation:
In the figure attached, Circle A is shown. There we can see that:
∠BC + ∠CD = ∠BAD
We know that Arc BC measures 96° and arc BAD measures 148°. Replacing this data into the equation and solving for Arc CD, we get:
96° + ∠CD = 148°
∠CD = 148° - 96°
∠CD = 52°
The medical students m>12,the temperature of students s=>25, and the ideal candidate c=<5
Answer:
https://iepa.org.au/network-news/it
Step-by-step explanation:
that link is answer
You find a common denominator (the bottom one) and then add the numerator (the top) but you don't add the denominator, you just make it the same