Let the fist integer be x, the second is x+20
the product of the numbers is:
x(x+20)
the sum of the numbers is:
x+x+20=2x+20
the sum of the above operations will give us:
2x+20+x^2+20x=95
x^2+22x+20=95
this can be written as quadratic to be:
x^2+22x-75=0
solving the above we get:
x=3 and x=-25
but since the integers should be positive, then x=3
the second number is x+20=3+20=23
hence the numbers are:
3 and 23
Answer: Domain = 
Range = 
Step-by-step explanation:
Here, the given function,
Since log( negative number ) = not defined
Also,
Hence, f(x) is defined if x - 1 > 0
⇒ x > 1
Thus, f(x) is defined for all the values that are greater than 1,
⇒ Domain of f(x) = All real number greater than 1,
= 
Now, for the interval ,
f(x) can be any real number.
Thus, the range of the given function =
Answer:
A. I can't quite see the question, but I'm pretty sure it's A
Step-by-step explanation:
Sin(A) = 1/3
Sin^2(A) + Cos^2(A) = 1
(1/3)^2 + cos^2(A) = 1
1/9 + cos^2(A) = 1
cos^2(A) = 1 - 1/9
cos^2(A) = 8/9
cos(A) = √(8/9)
√8 = √(2 * 2 * 2) = 2√2
√9 = 3
cos(A) = 2√2/3
Answer:
i dont know, ive never learned this haha. i sat here for at least 45-50 minutes trying to figure it out. sorry :/
Step-by-step explanation:
Answer:
x = - 1 and x = 5
Step-by-step explanation:
Given
(x - 3)² + 2(x - 3) - 8 = 0
Let u = x - 3, then
u² + 2u - 8 = 0 ← solve for u
(u + 4)(u - 2) = 0 ← in factored form
Equate each factor to zero and solve for u
u + 4 = 0 ⇒ u = - 4
u - 2 = 0 ⇒ u = 2
Convert back to x, that is
x - 3 = - 4 ( add 3 to both sides ) ⇒ x = - 1
x - 3 = 2 ( add 3 to both sides ) ⇒ x = 5
