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miv72 [106K]
3 years ago
14

Please Help !! I will reward brainliest asap

Mathematics
1 answer:
Arada [10]3 years ago
5 0
The answer is 1 

since 0! means 0 + 1 = 1
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PLEASE HELP!!<br><br> What is the slope of the line on the graph?
Amanda [17]

Answer:

Slope = (-1/3)

Step-by-step explanation:

Point 1: (-6, 6); Point 2: (6, 2)

            (x₁, y₁)                (x₂, y₂)          

        y₂ - y₁         2 - 6          -4            -4 ÷ 4         -1

m = ------------ = ----------- = ---------- = -------------- = -------

        x₂ - x₁        6 - (-6)      6 + 6        12 ÷ 4           3

y - y₁ = m(x - x₁)

y - 6 = (-1/3)(x + 6)

y - 6 = (-1/3)x - 2

   +6              +6

-------------------------

y = (-1/3)x + 4

I hope this helps!

8 0
1 year ago
Read 2 more answers
trapezoid BIRD is dilated to form trapezoid FROG. What corresponding angles is congruent to angle BIR? Type the answer in the bo
alexdok [17]

The answer is FRO

B is congruent to F

I is congruent to R

R is congruent to O

D is congruent to G

3 0
3 years ago
What best describes the asymptote of an exponential function of the form f(x)=b^x?
horrorfan [7]

It depends on the value of b


Exponential functions are defined for positive values of the base [ŧex] b [/tex]. Also, they're not defined if b=1, or at least let's say that this is a trivial case, since it is the constant function 1.


Case 0<b<1:

If the base sits between 0 and 1, the exponential function is constantly decreasing. The explanation is quite intuitive, assume for the sake of simpleness that b is rational. If it sits between 0 and 1, it means that it can be written as a fraction p/q, with p<q. So, if you give a large exponent to b, you obtain


\frac{p^x}{q^x},\quad p^x \ll q^x \text{ as } x \to \infty


On the other hand, if you consider negative exponents, you switch numerator and denominator and then raise to the same exponent the fraction q/p, which gets larger and larger.


So, if 0<b<1, we have


\lim_{x \to -\infty} b^x = \infty,\qquad \lim_{x \to \infty} b^x = 0


and thus 0 is a horizontal asymptote as x tends to (positive) infinity.


Case b>1:

This case is very similar, except all roles are inverted. Now you start with a fraction p/q where p>q. So, with positive, large exponents you get


\frac{p^x}{q^x},\quad p^x \gg q^x \text{ as } x \to \infty


And as before, negative exponents switch numerator and denominator, so the fraction becomes q/p and thus you have


\lim_{x \to -\infty} b^x = 0,\qquad \lim_{x \to \infty} b^x = \infty


So, again, 0 is a horizontal asymptote, but this time for x tending towards negative infinite.

6 0
3 years ago
Read 2 more answers
3. Simplify the following expression<br> 2a(a+3)-4a4a-7)
LiRa [457]

Answer:

-14a^2+6a-7

Step-by-step explanation:

8 0
4 years ago
A fruit bowl contains 3 apples, 4 pears, and 4 oranges. Kayla selects 2 fruits at random without replacement. What is the probab
love history [14]
Pick 1: 3 apples out of 11 pieces of fruit → 3/11
Pick 2: 4 oranges out of 10 pieces of fruit → 4/10 = 2/5

Pick 1 AND Pick 2
  3/11    x      2/5      =  6/55
3 0
4 years ago
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