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zheka24 [161]
4 years ago
10

a 120 watt light bulb uses about 0.1 kilowatt of electricity per hour. if electricity costs 0.20 per kilowatt hour, how much doe

it cost to have the bulb on for an hour
Mathematics
1 answer:
Allushta [10]4 years ago
5 0
A 120 watt light-bulb is a 0.120 kilowatt light bulb.

In one hour, it uses 0.120 kilowatt-hour of energy.

If electrical energy costs $0.20 per kilowatt hour, then that light bulb costs

        (0.120 kilowatt-hour / hour) x (0.20 dollar / kilowatt-hour) =

                            (0.120 x $0.20 / hour)  =  

                                       $0.024 / hour  =  <span>2.4¢  per hour </span>
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Select the correct answer from each drop-down menu.
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5 0
2 years ago
IS THE SQUARE ROUTE OF 7 OR 14/5 BIGGER
blsea [12.9K]
Root4 < root7 < root9
2 < root7 < 3
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5 0
4 years ago
Assume the random variable x has a binomial distribution with the given probability of obtaining a success. Find the following.
borishaifa [10]

Answer:

P(x > 10) = 0.6981.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this question:

n = 14, p = 0.8

P(x>10)

P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 11) = C_{14,11}.(0.8)^{11}.(0.2)^{3} = 0.2501

P(X = 12) = C_{14,12}.(0.8)^{12}.(0.2)^{2} = 0.2501

P(X = 13) = C_{14,13}.(0.8)^{13}.(0.2)^{1} = 0.1539

P(X = 14) = C_{14,14}.(0.8)^{14}.(0.2)^{0} = 0.0440

P(x > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) = 0.2501 + 0.2501 + 0.1539 + 0.0440 = 0.6981

So P(x > 10) = 0.6981.

8 0
3 years ago
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