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zheka24 [161]
3 years ago
10

a 120 watt light bulb uses about 0.1 kilowatt of electricity per hour. if electricity costs 0.20 per kilowatt hour, how much doe

it cost to have the bulb on for an hour
Mathematics
1 answer:
Allushta [10]3 years ago
5 0
A 120 watt light-bulb is a 0.120 kilowatt light bulb.

In one hour, it uses 0.120 kilowatt-hour of energy.

If electrical energy costs $0.20 per kilowatt hour, then that light bulb costs

        (0.120 kilowatt-hour / hour) x (0.20 dollar / kilowatt-hour) =

                            (0.120 x $0.20 / hour)  =  

                                       $0.024 / hour  =  <span>2.4¢  per hour </span>
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Nimfa-mama [501]

Answer: To simplify this problem you combine the like terms in the equation (numbers with the same variables.)

Demo: 12r + -4r = 8r

4 0
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Create a story that is about one page in length using at least five different algebraic expressions and/or equations. These are
nikitadnepr [17]

Answer:

A character is offered five different jobs. They all include an hourly wage, as well as a set weekly base pay. One example is a job that pays $8.50 an hour, plus an additional $25 bonus for the week. (Weekly base pay is what you automatically get paid for working the entire week. A bonus is money you earn in addition to the weekly base pay.) Story Starter 2: A character is searching for the best cell phone plan to buy. One plan costs $25 a month, plus $0.89 per minute used. Story Starter 3: A character is trying to decide which cab to choose from the five available. All the cabs have different rates per mile. They also charge different flat rates in addition to the rates per mile. One cab is offering a rate of $0.75 per mile, plus a flat fee of $25.

Step-by-step explanation:

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3 years ago
Find the missing term and the missing coefficient. (6a − )5a = a2 − 35a
djverab [1.8K]
So, (6a - X)*5a = Y*(a^2) - 35a 
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4 0
3 years ago
A movie theater charges $10 for adults and $6 for seniors. On a particular day when 357 people paid in admission, the total rece
olganol [36]

Answer:

Step-by-step explanation:

Determine the types of tickets involved.

There are student tickets and adult tickets.

Create a table to organize the information.

Type  

Number

   

Value ($)

   

Total Value ($)

 

Student    

6

 

Adult    

9

 

1

,

506

 

Step 2. Identify what you are looking for.

We are looking for the number of student and adult tickets.

Step 3. Name. Represent the number of each type of ticket using variables.

We know the number of adult tickets sold was  

5

 less than three times the number of student tickets sold.

Let  

s

 be the number of student tickets.

Then  

3

s

−

5

 is the number of adult tickets.

Multiply the number times the value to get the total value of each type of ticket.

Type  

Number

   

Value ($)

   

Total Value ($)

 

Student  

s

   

6

   

6

s

 

Adult  

3

s

−

5

   

9

   

9

(

3

s

−

5

)

 

1

,

506

 

Step 4. Translate: Write the equation by adding the total values of each type of ticket.

6

s

+

9

(

3

s

−

5

)

=

1506

 

Step 5. Solve the equation.

6

s

+

27

s

−

45

=

1506

33

s

−

45

=

1506

33

s

=

1551

s

=

47

students

 

Substitute to find the number of adults.

3

s

−

5

=

 number of adults

3

(

47

)

−

5

=

136

 adults

Step 6. Check. There were  

47

 student tickets at  

$6

 each and  

136

 adult tickets at  

$9

 each. Is the total value  

$1506

?

 We find the total value of each type of ticket by multiplying the number of tickets times its value; we then add to get the total value of all the tickets sold.

47

⋅

6

=

282

136

⋅

9

=

1224

_____

 

1506

✓

 

Step 7. Answer the question. They sold  

47

 student tickets and  

136

 adult tickets.

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3 years ago
Julie’s cell phone is 9 centimeters long. How many millimeters long is her cell phone
evablogger [386]
The answer is 90, there is 10 millimeters in 1 centimeter! So, if there is 9 centimeters, there will then be 90 millimeters!

Ps: I had my question up but someone reported it since I added a picture that would help you! :( 

Hope this does help though! You can always do the jumping trick with meters! That's how I learned :) 

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3 years ago
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