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kozerog [31]
3 years ago
12

Please help solve the equation and please don’t take advantage of the points.

Mathematics
1 answer:
vfiekz [6]3 years ago
5 0

Answer:

m=2/3, b=4

Step-by-step explanation:

Using the rise over run method, you can count from two points. Also since this line is positive. The b is found by seeing where the line crosses the y axis. It crosses at 4.

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Consider the following three statements:
Lena [83]
It's correlation. A causal relationship between two events exist if the occurrence of the first causes the other. The first event is called the cause and the second event is called the effect. A correlation between two variables does not imply causation. It may sound complicated but think of it like this. They are co related but they don't really effect one another, they just happen to occur at the same time. I really hope this helps. Let me know if I got anything wrong ok!
4 0
4 years ago
9 - (-8) • 3<br> Order of Operations
andrey2020 [161]

Answer:

33

Step-by-step explanation:

Order of Operations:

1. Parenthesis

2. Exponents

3. Multiplication/Division (left to right)

4. Addition/Subtract (left to right)

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7 0
3 years ago
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Mrs. Balcon owes the dentist $342. She wants to have her payments taken from her checking account over the next 7 1/2 months. By
kiruha [24]

Answer:

$45.60 per month

Step-by-step explanation:

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and get $45.60 per month

7 0
3 years ago
An airplane travels 6111 kilometers against the wind in 9 hours and 7911 kilometers with the wind in the same amount of time. Wh
natima [27]

Answer:

Speed of the plane in still air: 779\; {\rm km \cdot h^{-1}}.

Windspeed: 100\; {\rm km \cdot h^{-1}}.

Step-by-step explanation:

Assume that x\; {\rm km \cdot h^{-1}} is the speed of the plane in still air, and that y\; {\rm km \cdot h^{-1}} is the speed of the wind.

  • When the plane is travelling against wind, the ground speed of this plane (speed of the plane relative to the ground) would be (x - y)\; {\rm km \cdot h^{-1}}.
  • When this plane is travelling in the same direction as the wind, the ground speed of this plane would be (x + y)\; {\rm km \cdot h^{-1}}.

The question states that when going against the wind (v = (x - y)\; {\rm km \cdot h^{-1}},) the plane travels 6111\; {\rm km} in 9\; {\rm h}. Hence, 9\, (x - y) = 6111.

Similarly, since the plane travels 7911\; {\rm km} in 9\; {\rm h} when travelling in the same direction as the wind (v = (x + y)\; {\rm km \cdot h^{-1}},) 9\, (x + y) = 7911.

Add the two equations to eliminate y. Subtract the second equation from the first to eliminate x. Solve this system of equations for x and y: x = 779 and y = 100.

Hence, the speed of this plane in still air would be 779\; {\rm km \cdot h^{-1}}, whereas the speed of the wind would be 100\; {\rm km \cdot h^{-1}}.

3 0
2 years ago
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zepelin [54]
Second to last one is my guess
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4 years ago
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