X should be -1 and Y = 2
To make sure, plug in numbers
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-1 - 2 = -3 That works, now we try equation 2
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x + (3)(2) = 5
-1 + 6 = 5
This works to
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X = -1 and Y = 2

7 0

3 years ago

Which statement about square root x-5 - square root x = 5 is true?

Musya8 [376]

Hello,

Answer D

$\sqrt{x-5} - \sqrt{x} =5$
==> $(x-5) -2*\sqrt{(x-5)x}+x =25$
==> $2x-30=\sqrt{x(x-5)}$
==> $x-15=\sqrt{x(x-5)}$
==> $x^2-30x+225=x(x-5)$
==> $225=-5x+30x$
==> $25x=225$
==> $x=9$
But:

$\sqrt{9-5} - \sqrt{9}=\sqrt{4} - \sqrt{9}=2-3=-1$ ≠5

Explanation:

$\lim_{x \to \infty} \sqrt{x-5}- \sqrt{x}

$

$= \lim_{x \to \infty} \frac{(\sqrt{x-5}- \sqrt{x})*(\sqrt{x-5}+ \sqrt{x})}
{\sqrt{x-5}+ \sqrt{x}}$

$= \lim_{x \to \infty} \frac{(-5)}{\sqrt{x-5}+ \sqrt{x}}$

$= \lim_{x \to \infty} \frac{-5}{\infty}=0


$

7 0

3 years ago