Answer:
The answer to your question is the letter D.
Step-by-step explanation:
Data
First rectangle Second rectangle
length = 3 length = 3
width = 2 width = 2 + 4 = 6
Process
1.- Calculate the Perimeter of the first rectangle
Perimeter = 2l + 2w
Perimeter = 2(3) + 2(2)
= 6 + 4
= 10
2.- Calculate the perimeter of the second rectangle
Perimeter = 2(3) + 2(6)
Perimeter = 6 + 12
Perimeter = 18
3.- Compare both perimeters
Perimeter 1 is smaller than Perimeter 2 by 8 units
36 equally-likely outcome: (1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1),(6,2), (6,3), (6,4), (6,5), (6,6)
Solution:
Outcomes with first number being old number and second being even number: (1,2), (1,4), (1,6), (3,2), (3,4), (3,6), (5,2), (5,4), (5,6) = 9 outcomes
P(old,even) = 9/36 =1/4 = 0.25
Answer:
2x+2y=6
Step-by-step explanation:
-4x + -2y = -18
2x + 3y = 24
2x + 2y = 6
We would find the midpoint by applying the formula for determining the midpoint of a segment which is expressed as
Midpoint = (x1 + x2)/2, (y1 + y2)/2
From the given points,
x1 = 4, y1 = - 5
x2 = 6, y2 = 1
Midpoint = (4 + 6)/2, (- 5 + 1)/2
Midpoint = 10/2, - 4/2
Midpoint = 5, - 2
