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Sindrei [870]
3 years ago
15

Notebooks cost $1.20 each. This weekend they will be $.80 What percentage is the sale?

Mathematics
2 answers:
photoshop1234 [79]3 years ago
5 0
The sale is 33% off notebooks. This can be found by first subtracting .8 from 1.2

1.2-.8=.4    Now divide .4 by 1.2 to get your answer.

\frac{.4}{1.2}=.33

.33=33%

You can also solve this mentally because if you know your basic multiplication tables, 3*4=12 and so \frac{2}{3} of 12 would equal 8.

Does you understand it now?
Taya2010 [7]3 years ago
3 0
In the question it is already given that the actual cost of each notebook is $1.20. For the weekend, the notebooks would sold at a discounted rate of $0.80
he
The amount of discount during the weekend = (1.20 - 0.80) dollars
                                                                       = 0.40 dollars
So the amount of discount given during the weekend is $0.40
Now we need to find the percentage of discount given during the weekend.
Then
Percentage of discount during the weekend = (0.40/1.20) * 100
                                                                       = 0.33 * 100
                                                                       = 33
Then the percentage of discount given is 33%.

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Vlada [557]

The indefinite integral will be  \int (7x^2+8x-2)dx=\dfrac{7x^3}{3}+4x^2-2x+C)

<h3 /><h3>what is indefinite integral?</h3>

When we integrate any function without the limits then it will be an indefinite integral.

General Formulas and Concepts:

Integration Rule [Reverse Power Rule]:                                                              

\int x^ndx=\dfrac{x^{n+1}}{n+1}}+C

Integration Property [Multiplied Constant]:                                                        

\int cf(x)dx=c\int f(x)dx

Integration Property [Addition/Subtraction]:                                                      

\int [f(x)\pmg(x)]dx=\int f(x)dx\pm \intg(x)dx

[Integral] Rewrite [Integration Property - Addition/Subtraction]:

\int (7x^2+8x-2)dx=\int 7x^2dx+\int 8xdx    -\int 2dx          

[Integrals] Rewrite [Integration Property - Multiplied Constant]:  

\int (7x^2+8x-2)dx=7 \int x^2dx+ 8 \int xdx    -2\int dx            

[Integrals] Reverse Power Rule:    

\int (7x^2+8x-2)dx= 7(\dfrac{x^3}{3})+8(\dfrac{x^2}{2})-2x+C                                                            

Simplify:    

\int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                                                                                                      

So the indefinite integral will be \int (7x^2+8x-2)dx= \dfrac{7x^3}{3}+4x^2-2x+C                

To know more about indefinite integral follow

brainly.com/question/27419605

#SPJ4

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