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ipn [44]
3 years ago
14

Please help it will be fast and easy

Mathematics
1 answer:
mestny [16]3 years ago
8 0

Answer:

B

Step-by-step explanation:

36 candy

6 different types

if I pick random I'll get 1 of 6

.................................

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Using the defects method, which of these relationships represents the Law of Cosines if the measure of the included angle betwee
Radda [10]
Cosine Law:
c² = a² + b² - 2 a b cos C
Answer:
C ) area of square c² = area of square a² + area of square b²
- area of defect 1 - area of defect 2 
3 0
3 years ago
Read 2 more answers
∠1 and ∠2 are supplementary angles. If m∠1 = 77°, then m∠2 =
posledela

Answer:

B. 103°

Step-by-step explanation:

Supplementary angles add up to 180°, so we can find the measure of angle 2 by subtracting 77 from 180

180 - 77

= 103

So, m∠2 is 103°

7 0
2 years ago
Find the average rate of change of g(x) = 1x3 + 2 from x =<br> 1 to x = 4
Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

Explanation:

The

average rate of change

of g(x) over an interval between 2 points (a ,g(a)) and (b ,g(b) is the slope of the

secant line

connecting the 2 points.

To calculate the average rate of change between the 2 points use.

∣

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

g

(

b

)

−

g

(

a

)

b

−

a

a

a

∣

∣

∣

−−−−−−−−−−−−−−−

g

(

6

)

=

6

2

−

6

+

3

=

33

and

g

(

4

)

=

4

2

−

4

+

3

=

15

Thus the average rate of change between (4 ,15) and (6 ,33) is

33

−

15

6

−

4

=

18

2

=

9

This means that the average of all the slopes of lines tangent to the graph of g(x) between (4 ,15) and (6 ,33) is 9

3 0
3 years ago
Solve for the width in the formula for the area of a rectangle.
madam [21]
A = L * W
A / L = W <==

when A = 42 and W = 16.8
A / L = W
42/16.8 = W
2.5 = W <=== width = 2.5 inches
4 0
3 years ago
Read 2 more answers
GUYS PLZ HELP ME!!!!!!
siniylev [52]

Answer:

B E F G

Step-by-step explanation:

Polygons are 2 dimensional shapes with straight edges (no curved edges). The shape needs to be closed up entirely to be a polygon. It cannot have any intersecting line segments

A can't be a polygon because the shape isn't closed up entirely

C can't be a polygon because it is a 3d shape

D can't be a polygon because it has curved edges.

H can't be a polygon because it isn't closed up (there are no line segments).

I can't be a polygon because polygons cannot have intersecting lines

J can't be a polygon because polygons cannot have intersecting lines

I hope this helps! If it does, a rate or brainliest would be much appreciated. :)

7 0
3 years ago
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