The sum of the two digits of a number is 16. The number formed by reversing the digits is 18 more than the original number. Dete
rmine the original number.
Let t = the tens digit, u = the units digit, and u + t = 16. Which of the following equations would complete the system?
9t - 9u = 18
9u - 9t = 18
tu = ut + 18
2 answers:
9u-9t=18
original no. is 10t+u
reversed no. is 10u+t
so is (10u+t)-(10t+u)=18
hence, the ans is 9u-9t=18
The answer is B, 9u-9t=18
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I hope I helped (:
