I am having trouble with converges and diverges
1 answer:
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Hi there!
For any 45 45 90 right triangle, the length of the hypotenuse is always the square root of 2 times one of the legs.
To get the lengths of the leg, let's divide the length of the hypotenuse by the square root of 2.
We get the following:
When simplifying fractions like this, we want to avoid having radicals on the bottom. In order to remove the radical from the denominator, let's multiply the numerator and the denominator by the square root of 2.
We get the following:
That's your answer.
Have an awesome day! :)
- collinjun0827, Junior Moderator
For any 45 45 90 right triangle, the length of the hypotenuse is always the square root of 2 times one of the legs.
To get the lengths of the leg, let's divide the length of the hypotenuse by the square root of 2.
We get the following:
When simplifying fractions like this, we want to avoid having radicals on the bottom. In order to remove the radical from the denominator, let's multiply the numerator and the denominator by the square root of 2.
We get the following:
That's your answer.
Have an awesome day! :)
- collinjun0827, Junior Moderator