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miss Akunina [59]
2 years ago
11

(5√3-√27)^3 how do you prove that this is an integer?

Mathematics
2 answers:
mr Goodwill [35]2 years ago
5 0

Keys:

  • \left(a\cdot \:b\right)^n=a^nb^n

Step-by-step explanation:

\left(5\sqrt{3}-\sqrt{27}\right)^3\\\5\sqrt{3}-\sqrt{27}^3=\left(2\sqrt{3}\right)^3\\= 2\sqrt{3}\\\left(2\sqrt{3}\right)^3=2^3\left(\sqrt{3}\right)^3\\=2^3\left(\sqrt{3}\right)^3\\2^3=8\\=8\left(\sqrt{3}\right)^3\\=8\cdot \:3\sqrt{3}\\8\cdot \:3=24\\=24\sqrt{3}

kirill [66]2 years ago
4 0

Answer:

It is not an integer.

Step-by-step explanation:

(5\sqrt{3} -\sqrt{27} )^3\\\\=(\sqrt{3} *(5-3))^3\\\\=8*3*\sqrt{3} \\\\=24\sqrt{3} \\

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Answer:

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Hope this helps

8 0
4 years ago
In the past, the average age of employees of a large corporation has been 40 years. Recently, the company has been hiring older
earnstyle [38]

Answer:

Step-by-step explanation:

In the past, mean of age of employees

i.e. \mu = 40

Recently sample was taken

n = sample size = 60

Mean of sample = 45

Std dev of sample s = 16

H_0: \bar x = 40\\H_a: \bar x >40

(Right tailed test)

Since only population std deviation is known we can use t test only

Std error = \frac{s}{\sqrt{n} } \\=\frac{16}{\sqrt{61} } \\=2.049

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df = 60

p value =0.008739

Since p < 0.05 we reject null hypothesis

The mean age has increased.

5 0
3 years ago
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Darya [45]
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6 0
3 years ago
24 1/2% is equal to which
Lorico [155]

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Step-by-step explanation:

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3 years ago
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Nataly_w [17]

Answer:

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8 0
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