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melamori03 [73]
3 years ago
7

Given an array declared to hold 100 values, the smallest index that can be used with the array is

Computers and Technology
1 answer:
Aneli [31]3 years ago
8 0
In C influenced languages - 0.
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Different algorithms can be made to complete the same task in different ways.
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Answer:

True hope this helps you and everyone!

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3 years ago
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Suppose the m2 money supply is $13 trillion, including: $7 trillion in savings accounts $3 trillion in checking accounts $1 tril
tia_tia [17]

Answer:

M1 is equal to $ 4 trillion

Explanation:

M1 money supplies are liquid money supplies like cash, checkable deposits, traveler's check etc. It is equal to;

M1= coins and currency in circulation + checkable (demand) deposit + traveler's check.

M2 money supply are less liquid and is equated as;

M2 = M1 + savings deposit + money market fund + certificates of deposit + other time deposits.

Savings = $7 trillion

Checkable deposit = $3 trillion

Money market fund = $1 trillion

Currency = $1 trillion

Certificates of deposit = $1 trillion

M1 = currency + checkable deposit

= $1 + $ 3

= $4 trillion.

6 0
3 years ago
Suppose that you are asked to modify the Stack class to add a new operation max() that returns the current maximum of the stack
Advocard [28]

Answer:

Following are the code to the given points:

Explanation:

For point 8.1:

public String max()//defining a method max

{

   String maxVal=null;//defining a string variable that holds a value

   for(int x=0;x<n;x++)

   {

       if(maxVal==null || a[i].compareTo(maxVal)>0)//defining if blok to comare the value

       {

           maxVal=a[i];//holding value in maxVal variable

       }

   }

   return maxVal;//return maxVal variable value

}

For point 8.2:

public void push(String item)//defining a method push that accepts item value in a parameter

{

       a[n]=item;//defining an array to hold item value

       if(n==0 || item.compareTo(maxVals[n-1])>0)//use if to comare item value

       {

               maxVals[n]=item;//holding item value in maxVals variable

       }

       else

       {

               maxVals[n]=maxVals[n-1];//decreasing the maxVals value

       }

       n++;//incrementing n value

}

public String pop()//defining a method pop

{

       return a[--n];//use return value

}

public String max()//defining a method max

{

       return maxVals[n-1];//return max value

}

  • In the first point, the max method is declared that compares the string and returns its max value.
  • In the second point, the push, pop, and max method are declared that works with their respective names like insert, remove and find max and after that, they return its value.
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Which view shows how the document will look when printed?
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