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Alex17521 [72]
3 years ago
15

SELECT vendor_name, COUNT(*) AS number_of_invoices, MAX(invoice_total - payment_total - credit_total) AS balance_due FROM vendor

s v JOIN invoices i ON v.vendor_id = i.vendor_id WHERE invoice_total - payment_total - credit_total > (SELECT AVG(invoice_total - payment_total - credit_total) FROM invoices) GROUP BY vendor_name ORDER BY balance_due DESC When this query is executed, the rows will be sorted by _________.
Computers and Technology
1 answer:
shepuryov [24]3 years ago
3 0

Answer:

balance_due in descending sequence.

Explanation:

When this query is executed, the rows will be sorted by balance_due in descending sequence.

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To make something ready for some activity is to ________it.
WINSTONCH [101]

Answer:

prepare (e.g. SQL prepared statements)

parse/convert (e.g. parse a string as an int/convert an array to string)

Explanation:

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Did the Z3 computer invented by Konrad Zuse have a negative effect on society?
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Answer:

Explanation:

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Which statement opens a text file so that you can retrieve the information it contains?
vesna_86 [32]

Answer:

Answered below

Explanation:

aFile = open("books.txt", "r")

This code uses the function open() which takes two parameters. The first parameter is the file name while the second parameter is the mode in which you are accessing the file.

The "r" mode opens the file in a reading state. That is, you can only read from the file. This code completes the reading process

aFile.read( )

The "w" mode opens the file so you can write to it and make changes.

The "a" mode opens the file so you can add contents to it.

3 0
2 years ago
Instructions The population of town A is less than the population of town B. However, the population of town A is growing faster
weeeeeb [17]

Answer: The c++ program is given below.

#include <iostream>

using namespace std;

int main() {

float townA, townB, growthA, growthB, populationA, populationB;

    int year=0;    

cout<<"Enter present population of town A : ";

cin >> townA;  

cout<<endl<<"Enter present growth rate of town A : ";

cin >> growthA;

growthA = growthA/100;  

cout<<endl<<"Enter present population of town B : ";

cin >> townB;  

cout<<endl<<"Enter present growth rate of town B : ";

cin >> growthB;

growthB = growthB/100;  

do

{

    populationA = townA + (townA * growthA);

    populationB = townB + (townB * growthB);      

    townA = populationA;

    townB = populationB;      

    year++;      

}while(populationA < populationB);  

cout<<endl<<"After " <<year<< " years, population of town A is "<<populationA << " and population of town B is "<< population<<endl;

return 0;

}

Explanation:

All the variables for population and growth rate are declared with float datatype.

The user inputs the present population of both the towns.

The growth rate entered by the user is the percentage growth.

For example, town A has 10% growth rate as shown in the output image.

The program converts 10% into float as 10/100.

growthA = growthA/100;

growthB = growthB/100;

The above conversion is done to ease the calculations.

The year variable is declared as integer and initialized to 0.

The growth in population is computed in a do-while loop. After each growth is calculated, the year variable is incremented by 1.

The loop continues until population of town A becomes greater than or equal to population of town B as mentioned in the question.

Once the loop discontinues, the final populations of town A and town B and the years needed for this growth is displayed.

The new line is introduced using endl keyword.

The function main has return type int hence, 0 is returned at the end of the program.

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3 years ago
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Answer:

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Explanation:

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