Answer:
Step-by-step explanation:
when h(t)=0
-4.9 t²+19.6t=0
4.9t(-t+4)=0
either t=0 or t=4
so domain is 0≤t≤4
for range
h(t)=-4.9t²+19.6t
=-4.9(t²-4t+4-4)
=-4.9(t-2)²+19.6
so range is 0≤h≤19.6
The difference of the length of two different squares having area of 36 square meters and 49 square meters is 1 m.
According to the question,
We have the following information:
Two different squares have an area of 36 square meters and 49 square meters.
We know that the following formula is used to find the area of square:
Area = side*side
Side*side = 36
Side = √36
Side = 6 m
Now, side of the another square:
Side*side = 49
Side = √49
Side = 7 m
Now, the difference in the length of the sides of these two squares:
7-6
1 m
Hence, the difference of the length of two different squares having area of 36 square meters and 49 square meters is 1 m.
To know more about difference of the length here
brainly.com/question/20750630
#SPJ1
