Answer this question and I will mark you branilist

Nata [24]

The answer is 15x good luck on your homework buddy

7 0

3 years ago

Two sizes of cans of beans are similar. The thickness of the walls and bases are the same in both cans. The ratio of their surfa

agasfer [191]

Answer:

It costs $0.216 to make smaller can and $0.324 to make larger can

Step-by-step explanation:

Given:

The ratio of the surface areas = 4:9

Area of smaller cans = 36 sq in

Cost = $0.006 per square inch

To Find:

how much does it cost to make each can = ?

Solution:

Lets the area of the larger can be x

the ratio is 4 : 9

then 4x = 9.(36)

4x = 216

$x = \frac{216}{4}$

x = 54

The area of the larger can is 54 sq in

Now the cost of making the smaller can = $36 \times 0.006$ = $0.216

The cost of making the Larger can = $54 \times 0.006$ =$0.324

4 0

3 years ago

8x - 9 - 5x = 3x - 36 - 18x

makkiz [27]

Answer:

$8x - 9 - 5x = 3x - 36 - 18x \\ 8x - 5x - 9 = 3x - 18x - 36 \\ 3x - 9 = - 15x - 36 \\ 3x = - 15x - 36 + 9 \\ 3x = - 15x - 27 \\ 3x + - 15x = - 27 \\ - 12x = - 27 \\ x = \frac{ 27}{12}$

8 0

3 years ago

Adam went to Target and bought items for $45.05, $9.29, and $0.89. How much did these three

andriy [413]

The answer is 55. 23 dollars because if you add 45.05
+. 9.29
—————————
54.34
+. 0. 89
—————————
55.23

5 0

3 years ago

The realtor and her clients do not know the average home sale price for all of Guelph (500 was actually just a guess). However,

strojnjashka [21]

Answer:

a) The 99% confidence interval would be given by (346.708;453.292)

b) The 99% confidence interval would be given by (338.445;461.555)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=400$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=80$ represent the population standard deviation

n=15 represent the sample size

2) Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

Now we have everything in order to replace into formula (1):

$400-2.58\frac{80}{\sqrt{15}}=346.708$

$400+2.58\frac{80}{\sqrt{15}}=453.292$

So on this case the 99% confidence interval would be given by (346.708;453.292)

3) Part b

For this case we don't know the population deviation so we need to use the t distribution instead the normal standard distribution.

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

We need to find the degrees of freedom first df=n-1=15-1=14

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,14)".And we see that $t_{\alpha/2}=2.98$

Now we have everything in order to replace into formula (1):

$400-2.98\frac{80}{\sqrt{15}}=338.445$

$400+2.98\frac{80}{\sqrt{15}}=461.555$

So on this case the 99% confidence interval would be given by (338.445;461.555)

4 0

3 years ago