<span>The mean of a set of data is 148.87 and its standard deviation is 68.29. Find the z score for a value of 490.19
the z-score is given by:
z=(x-</span>μ<span>)/</span>σ
plugging in the values in the expression we get:
z=(490.19-149.87)/68.29
z=340.32/68.29
z=4.9835
Answer:
Step-by-step explanation:
The question says that the fish population of an area is being tracked and a certain of 35 were collected,tagged and released.
Later another sample was collected and it revealed that 13% of those fishes caught were the ones tagged previously.
The estimated number of fishes in that area will be:
Let X= number of fishes available in that area
13 percent of fishes caught at the second sample collection were tagged
Number of fishes collected are 35
13/100×X= 35
X= 3500/13
X= 269
The number of fishes in the pond is around 269
Answer:
73/14
Step-by-step explanation:
Answer:
(-3,-5)
Step-by-step explanation:
2x=-6
x=-3
24+3y=9
3y=-15
y=-5
