Answer:
a) 29
b) 0
c) 7
d) 3/8
Step-by-step explanation:
Whenever you're facing a clock maths problem, the solution always have to be < to the number of hours in the given clock. If it's > the number of hours of the given clock, you subtract the number of hours until you get a result <= the number of clock hours.
If the result is negative, you add the clock hours.
a) 21 - 33 = -12 , so -12 + 41 = 29
b) 13 * 4 = 52, then do 52 - 52 = 0, since answer has to be < 52.
c) 11+19 = 30, 30 - 23 = 7
d) 3/8 = 3/8, since 3/8 <= 15, you're also fine.
Total coverage = 0.85 x 185,000 = $157,250
Coverage for Loss of Use = 0.25 x 157250 = $39,312.50
First i dont know what is the meaning of the mmc098-2.jpg, mmc098-3.jpg and <span>mmc098-4.jpg. but base from what you had written is a set of equation where you solve the values of each variables. but unfortunately i cant solved it because of what you have written there. please give me the correct equation so i can solve it</span>
Answer:
c)-5(3x+2y)(3x-2y)
Step-by-step explanation:
1) lets find out if -45 and 20 have a GCF
-45 and 20 are both dividable by -5 so
-5(9x^2-4y^2)
1) you can see that 9 and -4 are perfect square so:
-5(3x+2y)(3x-2y)
Recheck:
1) lets use FOIL to see if this is right(if its right we will get back our original equation)
-5(9x^2-6xy+6xy-4y^2)
-5(9x^2-4y^2)
-45x^2+20y^2
hope this helps!
