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malfutka [58]
3 years ago
11

11.

Computers and Technology
1 answer:
kodGreya [7K]3 years ago
6 0

Answer:

The basic difference between finite and infinite is the number of times it runs and ends. The loop is basically a set of instructions that keeps repeating itself.

The finite loop ends after running for a finite times. This body of finite loop will stop executing after certain condition is reached. Hence the finite loop body keeps executing itself finite number of times.

An infinite loop keeps running and repeating itself endlessly.This loop never ends. This loop can be the result of an error in a program. For example when no stopping or exit condition is specified in the program.

Explanation:

Example of finite loop:

Lets take for loop as an example:

for(int i =0; i<=5; i++)

{ cout<<i<<endl; }

Now the loop starts from i=0

Next it enters the body of loop to execute the statement: cout<<i; which means that the value of i is displayed on the output screen.

This loop keeps executing until the value of i exceeds 5.

At first iteration 0 is printed on the output screen, at second iteration 1, at third iteration 2, at fourth iteration 3, fifth iteration 4, sixth iteration 5. After each of these iterations, the value of i is incremented by 1.

When 5 is printed, then at the next iteration the specified condition i.e. i<=5 gets false as the value of i now becomes 6 after incremented by 1.

So the loop stops running. So this means that loop ran for finite times and stopped after the a certain condition is reached. The output is:

0

1

2

3

4

5

Example of infinite loop:

Lets take while loop:

int i = 6;

    while (i >=5)

    {         cout<< i;

             i++;     }

In the above example, the loop will run infinite times. Here the value of i is initialized to 6. Then while loop is used which checks the condition which is the value of i is greater than or equal to 5. If the condition is true, the body of the loop starts executing which prints the value of i. Lets see what happens at each iteration:

1st iteration: i>=5 is True because i=6 and 6 is greater than 5. The program control enters the body of loop. The statement cout<<i prints 6. Next the value of i is incremented by 1 and it becomes 7.

2nd iteration: i>=5 is True because i=7 and 7 is greater than 5. The program control enters the body of loop. The statement cout<<i prints 7. Next the value of i is incremented by 1 and it becomes 8.

This loop will repeat itself infinite times and never stops as i will always have value greater than 5. So this is the example of infinite loop.

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Write only in C, not C++.
yawa3891 [41]

Answer:

#include <iostream>

using namespace std;

int main() {

  int k;

double d;

string s;

cin >> k >> d >> s;

cout << s << " " << d << " " << k << "\n" << k << " " << d << " " << s; }

                                                                   

Explanation:

k is int type variable that stores integer values.

d is double type variable that stores real number.

s is string type variable that stores word.

cin statement is used to take input from user. cin takes an integer, a real number and a word from user. The user first enters an integer value, then a real number and then a small word as input.

cout statement is used to display the output on the screen. cout displays the value of k, d and s which entered by user.

First the values of k, d and s are displayed in reverse order. This means the word is displayed first, then the real number and then the integer separated again by EXACTLY one space from each other. " " used to represent a single space.

Then next line \n is used to produce a new line.

So in the next line values of k, d and s are displayed in original order (the integer , the real, and the word), separated again by EXACTLY one space from each other.

The program along with the output is attached.

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Answer:

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