in the <u>star</u> topology configuration, hosts are connected to each other through a central controller which assumes all responsibility for routing messages to the appropriate host.
Define topology.
When a geometric object <u>is stretched, twisted, crumpled, or bent without closing or opening holes, ripping, gluing, or passing through itself, certain features are kept</u>. This is known as topology in mathematics.
<u>The study of datasets using </u><u>topological </u><u>methods</u> is known as topological-based data analysis (TDA) in applied mathematics. <u>Open sets are a convenient way to define the basic </u><u>topological </u><u>notions of continuity, compactness, and connectedness</u>.
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A site, a domain, or an organizational unit in an active directory is referred to as a <u>container.</u>
<h3>What is a domain?</h3>
A domain is a name of a site of a name that is given online to a website. This name is the identity of the website. This gives the detail of your site, and your site will be identified by this name.
An active directory is a function developed by Microsoft. It maintains the network of a windows domain. This contains the site, domain, and together called a container.
Thus, a container in an active directory is a site, a domain, or an organizational unit.
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Answer:
It is either an internal IP address or it is a private IP address.
Explanation:
Answer:
a. 1 is a packet, 2 is data, 3 is a frame.
Explanation:
And what is not mentioned is segment which used TCP/UDP and is part of Transport layer. The packet carries the destination and sender IP address, and is part of the Network Layer. The frame has the Mac address of destination device and senders device and is part of data link layer.
Hence segment has no IP address, hence b. is not correct. Also, data cannot have the IP Address, and Frame has the MAC address, Hence, the above answer. And this arrangement is part of Data Encapsulation.
Also keep in mind data can be anything like a series of bits, or any and it can or not have a header.
Give the type and value of each result of the following Java expressions. a. (5 / 2) * 2.0 type is float value is 4.0 b. (5/2.0) * 2 type is integer value is 5c. "1.3" + "5.2" type is string value is 1.35.2d. 1 + 7.0 + "2" + "x" this will produce an error because we cannot add variables of different type
