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Zigmanuir [339]
3 years ago
5

Organize the following polynomial expressions from least to greatest based on their degree:

Mathematics
2 answers:
bixtya [17]3 years ago
7 0
The correct answer is 
III, I, II, IV
8a - 5
6x2
18x3 + 5ab - 6y
4x3y + 3x2 - xy - 4
My name is Ann [436]3 years ago
7 0

Answer:

The correct answer is  C)

III, I, II, IV

8a - 5

6x2

18x3 + 5ab - 6y

4x3y + 3x2 - xy - 4

Step-by-step explanation:

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Write an equation of a line that passes through the point (2,0) and is perpendicular to the line y = − 1/2 x + 3.
tatyana61 [14]

Answer:

Step-by-step explanation:

5 0
3 years ago
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A process produces batches of a chemical whose impurity concentrations follow a normal distribution with a variance of175. A ran
Tom [10]

Answer:

the probability that the sample variance exceeds 3.10 is 0.02020 ( 2,02%)

Step-by-step explanation:

since the variance  S² of the batch follows a normal distribution , then for a sample n of  20 distributions , then the random variable Z:

Z= S²*(n-1)/σ²

follows a χ² ( chi-squared) distribution with (n-1) degrees of freedom

since

S² > 3.10 , σ²= 1.75 , n= 20

thus

Z > 33.65

then from χ² distribution tables:

P(Z > 33.65) = 0.02020

therefore the probability that the sample variance exceeds 3.10 is 0.02020 ( 2,02%)

8 0
3 years ago
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68.76−5.23<br><br> A 16.46<br><br> B 18.53<br><br> C 63.53<br><br> D 73.99
Romashka [77]
The answer is 63.53 subtracts 5.23 from 68.76


6 0
3 years ago
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Slove the inequality 5(x + 1) &lt;25<br> x &lt; 4<br> x &gt; -4<br> x &gt; 4<br> Pls help meee
viktelen [127]

Algebra

Use the distributive property to make 5x+5.

5x+5<25

Subtract 5 from both sides.

5x<20

Divide both sides by five.

x<4

7 0
3 years ago
A sphere of radius r is cut by a plane h units above the equator, where
Anika [276]
Consider the top half of a sphere centered at the origin with radius r, which can be described by the equation

z=\sqrt{r^2-x^2-y^2}

and consider a plane

z=h

with 0. Call the region between the two surfaces R. The volume of R is given by the triple integral

\displaystyle\iiint_R\mathrm dV=\int_{-\sqrt{r^2-h^2}}^{\sqrt{r^2-h^2}}\int_{-\sqrt{r^2-h^2-x^2}}^{\sqrt{r^2-h^2-x^2}}\int_h^{\sqrt{r^2-x^2-y^2}}\mathrm dz\,\mathrm dy\,\mathrm dx

Converting to polar coordinates will help make this computation easier. Set

\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\var\phi\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi

Now, the volume can be computed with the integral

\displaystyle\iiint_R\mathrm dV=\int_0^{2\pi}\int_0^{\arctan\frac{\sqrt{r^2-h^2}}h}\int_{h\sec\varphi}^r\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\varphi\,\mathrm d\theta

You should get

\dfrac{2\pi}3\left(r^3\arctan\dfrac{\sqrt{r^2-h^2}}h-\dfrac{h^3}2\left(\dfrac{r\sqrt{r^2-h^2}}{h^2}+\ln\dfrac{r+\sqrt{r^2-h^2}}h\right)\right)
5 0
3 years ago
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