Consecutive odd integers are 2 apart
they are x and x+2
the product (x times (x+2)) is 1 less than 4 times their sum
x(x+2)=-1+4(x+x+2)


![x^2+2x=8x+7 minus (8x+7) from both sides [tex]x^2-6x-7=0](https://tex.z-dn.net/?f=x%5E2%2B2x%3D8x%2B7%20minus%20%288x%2B7%29%20from%20both%20sides%20%5Btex%5Dx%5E2-6x-7%3D0)
factor
what numbers multliply to get -7 and add to get -6?
-7 and 1
(x-7)(x+1)=0
set equal to 0
x-7=0
x=7
x+1=0
x=-1
so the x can be 7 or -1
the other number (x+2) can be 7 or 1
test each
7 and 9
7(9)=-1+4(7+9)
63=-1+4(16)
63=-1+64
63=63
true
-1 and 1
-1(1)=-1+4(-1+1)
-1=-1+4(0)
-1=-1+0
-1=-1
true
the 2 integers can be 7 and 9 or -1 and 1 (both pairs of numbers work)
Answer:
(1, 2)
Step-by-step explanation:
2x-y=0
4x-2=2
-----------
y=2x-0
y=2x
-------------
4x=2+2=4
4x=4
x=4/4=1
---------------
y=2(1)=2
x=1, y=2.
To solve these questions, use this formula:
X3= F(X1-X2)
Y3= F(Y1-Y2)
Where X3 is the X value in the coordinate your solving for, F is the fraction, X1 is the first X and X2 is the second X
Plug in your numbers to fit this:
X3= 1/4 x (0--2)
Y3= 1/4 x (4- -3)
By solving you get:
(-.5, 1.75)
Answer:
M+4.63=T
Step-by-step explanation:
M represents the amount that he spent on his groceries. T is total
Answer:
Mia got 8 incorrect. She scored 72/80.
Step-by-step explanation: