With what? I might be able to help
A right triangle has one leg with unknown length, the other leg with length of 5 m, and the hypotenuse with length 13 times sqrt 5 m.
We can use the Pythagorean formula to find the other leg of the right triangle.
a²+b²=c²
Where a and b are the legs of the triangle and c is the hypotenuse.
According to the given problem,
one leg: a= 5m and hypotenuse: c=13√5 m.
So, we can plug in these values in the above equation to get the value of unknown side:b. Hence,
5²+b²=(13√5)²
25 + b² = 13²*(√5)²
25 + b² = 169* 5
25+ b² = 845
25 + b² - 25 = 845 - 25
b² = 820
b =√ 820
b = √(4*205)
b = √4 *√205
b = 2√205
b= 2* 14.32
b = 28.64
So, b= 28.6 (Rounded to one decimal place)
Hence, the exact length of the unknown leg is 2√205m or 28.6 m (approximately).
answer is C 1/4
see attached picture, it is not exact but with rounding it comes out correct.
Answer:
A) I) 49 teams
II)63 teams
B) 28 teams
Step-by-step explanation:
A) a team of 5 boys and 6 Girls
=7C5+ 8C6
= 21+28
= 49 teams
a team of 6 boys and 5 girls
= 7C6 + 8C5
= 7+56
= 63 teams
B) one girl is kept constant already and a guy has injury
Girls remaining to choose from 7
Boys remaining to choose from 6
= 1 +7C5 + 6C5
= 1+21+6
= 28 teams
