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Nonamiya [84]
2 years ago
11

Which block has a volume of 90 cm3?

Mathematics
1 answer:
jeyben [28]2 years ago
4 0

Answer:

The volume of c. figure is equal to 90 cm³

Step-by-step explanation:

These are the cuboids

The volume of a cuboid = l×b×h

A. 2×6×5

=> 60 cm³

B. 8×2×4

=> 64 cm³

C. 5×6×3

=> 90 cm³

D. 3×7×2

=> 42 cm ³

so, the volume of c. cuboid is equal to 90 cm ³

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Drag each tile to the correct location on the table. Match each sentence to the term it’s describing.
Butoxors [25]

Answer:

  see below

Step-by-step explanation:

The premium is your cost for the insurance, paid to the insurance company.

The deductible is your cost for a claim, paid to settle your liability.

The limit is the maximum the insurance will pay for a given incident.

3 0
3 years ago
What is an equation of the line that passes through the point<br> (-2,-8) and has a slope of 3?
nignag [31]

Answer:

y = 3x - 2

Step-by-step explanation:

Use the point-slope equation since we are given a point that the line passes through and its slope:

y - y1 = m(x - x1)

(-2, -8), m = 3

Substitute these values into the equation.

  • y - (-8) = 3(x - (-2))
  • y + 8 = 3(x + 2)
  • y + 8 = 3x + 6
  • y = 3x - 2

The equation of the line that passes through the point (-2, -8) and has a slope of 3 is y = 3x - 2.

7 0
2 years ago
Filipo is building a rectangular sandbox . The length of the sandbox is 1 foot longer than twice the width of the sandbox .the p
Alla [95]

Answer:

Part A : D.) 2w + 2(2w+ 1) = 29

Part B : Length of the sandbox is 10 feet.

Step-by-step explanation:

Given,

Perimeter = 29 ft

We need to find the equation for the perimeter and also the length of the sandbox.

Solution,

Let the width of the sandbox be 'w'.

Now as per question said;

The length of the sandbox is 1 foot longer than twice the width of the sandbox.

So we can say that;

Length = 2w+1

Now we know that the perimeter is equal to the sum of twice of length and width.

framing in equation form, we get;

Perimeter = 2(2w+1)+2w

we have given the perimeter, so on substituting the value, we get;

29=2(2w+1)+2w

Hence The equation used to find the width is  29=2(2w+1)+2w.

Now we solve for 'w'.

Applying distributive property, we get;

4w+2+2w=29\\\\6w+2=29

Subtracting both side by '2' we get

6w+2-2=29-2\\\\6w=27

Dividing both side by 6 we get;

\frac{6w}{6}=\frac{27}{6}\\\\w=4.5\ ft

Width of the sandbox = 4.5 ft

Length of the sandbox = 2w+1=2\times4.5 +1 = 9+1=10\ ft

Hence Length of the sandbox is 10 feet.

3 0
3 years ago
Ramonita measured the height of a tree to be 11 feet. One month later, she measured the tree to be 11.75 feet tall. Two months a
DedPeter [7]
Hi.

To formally answer your question:

D. y = 0.75<em>x</em> + 11

We can prove this by substituting <em>x</em> with 1 (the initial measurement)

y = 0.75(1) + 11 = 11.75

~
3 0
3 years ago
Simplify the expression. 1/3r + 1/4 + 2/3r + 3/4​
expeople1 [14]

Answer:

r+1

Step-by-step explanation:

4 0
3 years ago
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